1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gnoma [55]
3 years ago
15

A football quarterback throws a football for a long pass. While in the motion of throwing, the quarterback moves the ball , star

ting from rest, and completes the motion in . Assuming the acceleration is constant, what force does the quarterback apply to the ball during the pass
Physics
1 answer:
sergejj [24]3 years ago
5 0

This question is incomplete, the complete question is;

A football quarterback throws a 0.408 kg football for a long pass. While in the motion of throwing, the quarterback moves the ball 1.909 m, starting from rest, and completes the motion in 0.439 s. Assuming the acceleration is constant, what force does the quarterback apply to the ball during the pass ;

a) F_throw = 8.083 N

b) F_throw = 9.181 N

c) F_throw = 2.284 N

d) F_throw = 16.014 N

e) None of these is correct

Answer:

the quarterback applied a force of 8.083 N to the ball during the pass

so Option a) F_throw = 8.083 N is the correct answer

Explanation:

Given that;

m = 0.408 kg

d = 1.909 m

u = 0 { from rest}

t = 0.439 s

Now using Kinetic equation

d = ut + 1/2 at²

we substitute

1.909 = (0 × 0.439) + 1/2 a(0.439)²

1.909 = 0 + 0.09636a

1.909 = 0.09636a

a = 1.909 / 0.09636

a = 19.8111 m/s²

Now force applied will be;

F = ma

we substitute

F = 0.408 ×  19.8111

F = 8.0828 ≈ 8.083 N

Therefore the quarterback applied a force of 8.083 N to the ball during the pass

so Option a) F_throw = 8.083 N is the correct answer

You might be interested in
Suppose a 0.04-kg car traveling at 2.00 m/s can barely break an egg. What is the min
Paha777 [63]

Answer: The correct answer is option (A).

Explanation:

Momentum of the car with 0.04 kg mass , which travelling with velocity of 2.00 m/s

P_1=mass\times velocity=m_1\times v_1=0.04 kg\times 2.00 m/s=8.00 kg m/s

Then the maximum speed of the another car in order to not to break the eggs will be same as first car:

P_1=P_2

0.08 kg m/s=m_2\times v_2=0.08 kg\times v_2

v_2=1 m/s

Speed slightly more than 1 m/s will increase the momentum of second car and the eggs will break. So, from the given options the minimum speed need by the second car will be 1.42m/s.

4 0
4 years ago
What is rectilinear propagation of light?​
nignag [31]

Answer:

Rectilinear propagation describes the tendency of electromagnetic waves to travel in a straight line. Light does not deviate when travelling through a homogeneous medium, which has the same refractive index throughout; otherwise, light suffers refraction.

3 0
3 years ago
Read 2 more answers
As the wavelength of an electromagnetic wave ___ the frequency of the wave ________.
adoni [48]

Answer:

As the wavelength of an electromagnetic wave _decrease__ the frequency of the wave _increase_______.

Explanation:

What is the relationship between frequency and wavelength?

Wavelength and frequency of light are closely related. The higher the frequency, the shorter the wavelength. Because all light waves move through a vacuum at the same speed, the number of wave crests passing by a given point in one second depends on the wavelength.

That number, also known as the frequency, will be larger for a short-wavelength wave than for a long-wavelength wave. The equation that relates wavelength and frequency is:

V= fλ

where v= velocity

           f= frequency

            λ = wavelength

⇒ f = v/λ  

also f ∝ 1/λ

For electromagnetic radiation, the speed is equal to the speed of light, c, and the equation becomes:

C= fλ

where c= Speed of light

           f= frequency

            λ = wavelength

⇒ f = v/λ  

also f ∝ 1/λ

8 0
4 years ago
A spherical Christmas tree ornament is 8.00 cm in diameter. What is the magnification of an object placed 12.0 cm away from the
LiRa [457]

The magnification of the ornament is 0.25

To calculate the magnification of the ornament, first, we need to find the image distance.

Formula:

  • 1/f = u⁻¹+v⁻¹.................... Equation 1

Where:

  • f = Focal length of the ornament
  • u = image distance
  • v = object distance.

make u the subject of the equation

  • u = fv/(f+v)................ Equation 2

From the question,

Given:

  • f = 8/2 = 4 cm
  • v = 12 cm

Substitute these values into equation 2

  • u = (12×4)/(12+4)
  • u = 48/16
  • u = 3 cm.

Finally, to get the magnification of the ornament, we use the formula below.

  • M = u/v.................. Equation 3

Where

  • M = magnification of the ornament.

Substitute these values above into equation 3

  • M = 3/12
  • M = 0.25.

Hence, The magnification of the ornament is 0.25

8 0
3 years ago
An elevator lifts a total mass of 1800 kg, a distance of 60 m in 60 s. How much power does the elevator generate?
emmainna [20.7K]

Answer:

17640

Explanation:

Power = workdone/time

Power = (force x displacement)/time

Power = (mg x 60)/60

Power = (1800 x 9.8 x 60)/60

=> power = 17640 watt

3 0
3 years ago
Other questions:
  • What unit is used when measuring the push that cause a charge to move
    10·1 answer
  • How might burning fossil fuels affect the composition of gases in the atmosphere?
    12·1 answer
  • How fast does the moon rotate around the Earth?
    6·2 answers
  • How are magnetic field lines like electric field lines?
    6·2 answers
  • According to the circular-flow model, which do producers provide to consumers?
    6·1 answer
  • If a transverse wave travels 10 meters in 5 seconds,what is its speed?
    14·2 answers
  • WILL GLADLY GIVE BRAINIEST FOR THIS EASY QUESTION
    9·2 answers
  • The initial speed of each block is v0 = 6.92 m/s, and each incline slopes upward at an angle of θ = 50.0°. The block on the shor
    7·1 answer
  • When an object is placed within the focal length of a convex lens, the image appears on the same side as the object itself. This
    8·1 answer
  • Calculate the amount of heat needed to increase the temperature of 200 grams of water at 10°C to 95°C.
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!