Question

A spherical Christmas tree ornament is 8.00 cm in diameter. What is the magnification of an object placed 12.0 cm away from the ornament

Answer 1

The magnification of the ornament is 0.25

To calculate the magnification of the ornament, first, we need to find the image distance.

Formula:

• 1/f = u⁻¹+v⁻¹.................... Equation 1

Where:

• f = Focal length of the ornament
• u = image distance
• v = object distance.

make u the subject of the equation

• u = fv/(f+v)................ Equation 2

From the question,

Given:

• f = 8/2 = 4 cm
• v = 12 cm

Substitute these values into equation 2

• u = (12×4)/(12+4)
• u = 48/16
• u = 3 cm.

Finally, to get the magnification of the ornament, we use the formula below.

• M = u/v.................. Equation 3

Where

• M = magnification of the ornament.

Substitute these values above into equation 3

• M = 3/12
• M = 0.25.

Hence, The magnification of the ornament is 0.25