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maxonik [38]
4 years ago
11

7x – 5(х + 8) = 5х – 28​Step-by-step PLEASE!!!!

Mathematics
2 answers:
MariettaO [177]4 years ago
7 0

Answer:

-4

Step-by-step explanation:

7x – <u>5(х + 8) </u>= 5х – 28

7x - <u>5x</u> + (-40) = <u>5x</u> - 28

   + 5x         + 5x

 <u>7x</u> + (-40) = <u>10x</u> - 28

- 7x             -  7x

<u>-40</u> = 3x - <u>28</u>

+ 28       + 28

-12 = 3x

Then divide.

-4

Andrei [34K]4 years ago
5 0

Answer:

Step-by-step explanation:

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The answer is that when you put the LMN. You can rotate it. Then we know it is similar.

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-6x – 29 = 5x – 7<br> What answer
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x=-2

Step-by-step explanation: :)

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Gohan earned scores of 95, 100, 65, 95, 75, 98, 100, 55, 100, 45 on his last ten quizzes. What is the mean of his quiz scores? W
irinina [24]

Answer: Mean= 82.8

Median= 95

Mode=100

Step-by-step explanation:

Mean is the average of the scores

Mean= 95+100+65+95+75+98+100+55+100+45 =828/10= 82.8

To get the median, we rearrange the numbers in either ascending or descending order.

45,55,65,75,95,95,98,100,100,100

Median= 95

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4 years ago
What is the value represented by the letter A on the box plot of the data? {10, 12, 15, 21, 24, 30} Enter your answer in the box
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How do you simplify <img src="https://tex.z-dn.net/?f=7%5Csqrt%5B4%5D%7B80pq%5E%7B2%7Dr%5E%7B8%7D%20%20%7D" id="TexFormula1" tit
kondor19780726 [428]

Answer:

14 ( 5)^{\frac{1}{4}} p^{\frac{1}{4}} q^{\frac{1}{2}} r^{2}

Step-by-step explanation:

The expression to simplify in this problem is

7\sqrt[4]{80pq^2r^8}

Which can be rewritten as

7(80pq^2r^8)^{\frac{1}{4}}

Or also as

7\cdot 80^{\frac{1}{4}} \cdot p^{\frac{1}{4}} \cdot (q^2)^{\frac{1}{4}} \cdot (r^8)^{\frac{1}{4}}

Now we can apply the following rule for the calculation of the power of a power:

(a^m)^n = a^{m\cdot n}

So we get:

7\cdot 80^{\frac{1}{4}} \cdot p^{\frac{1}{4}} \cdot q^{\frac{1}{2}} \cdot r^{2}

Which can therefore be rewritten as

7\cdot (2^4\cdot 5)^{\frac{1}{4}} \cdot p^{\frac{1}{4}} \cdot q^{\frac{1}{2}} \cdot r^{2}

And so, we get

7\cdot 2 \cdot ( 5)^{\frac{1}{4}} \cdot p^{\frac{1}{4}} \cdot q^{\frac{1}{2}} \cdot r^{2}

which can be finally rewritten as

14 ( 5)^{\frac{1}{4}} p^{\frac{1}{4}} q^{\frac{1}{2}} r^{2}

6 0
4 years ago
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