The control group is the plant without the music because nothing is being done to it. while the experimental group is the plant with music because you are testing it in a different environment (the music).
I think is true not sure but it might be
Answer:
1.33 moles CO2
Explanation:
The number you are converting is 58.4 g CO2, so you start with this value. The conversion factor is 44.0 g/mol CO2. In order to cross out the grams, the grams must go on the bottom of the conversion factor.
1 mol CO2
58.4 g CO2 x -------------------------- = 1.33 moles CO2
44.0 grams
The answer has three sig figs.
Answer:
The percent isotopic abundance of Cu-65 is 30.79 %.
The percent isotopic abundance of Cu-63 is 69.21 %.
Explanation:
we know there are two naturally occurring isotopes of carbon, Cu-63 (62.9298 amu) and Cu-65 (64.9278 amu)
First of all we will set the fraction for both isotopes
X for the isotopes having mass 62.9298 amu
1-x for isotopes having mass 64.9278 amu
The average atomic mass of copper is 63.546 amu.
we will use the following equation,
62.9298 x + 64.9278 (1-x) = 63.546
62.9298x + 64.9278 - 64.9278x = 63.546
62.9298x - 64.9278x = 63.546 - 64.9278
-1.998 x = -1.3828
x=-1.3828 / -1.998
x= 0.6921
0.6921 × 100 = 69.21 %
69.21 % is abundance of Cu-63 because we solve the fraction x.
now we will calculate the abundance of Cu-65.
(1-x)
1-0.6921 = 0.3079
0.3079 × 100 = 30.79 %
30.79 % for Cu-65.
You know if it's endothermic or exothermic by doing the enthalpy reaction. If the change of temperature is negative then it is exothermic, while positive is endothermic.
If you get -22K then its exothermic, but if you get +22 its endothermic.