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postnew [5]
3 years ago
14

What is the electron configuration of Iron

Chemistry
1 answer:
Novay_Z [31]3 years ago
5 0

The electron configuration of Iron is:

[Ar] 3d⁶4s²

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How many molecules of water can be produced from 46.72 liters of C8H18? 2\:C_8H_{18}\:+\:25\:O_2\:\:\Longrightarrow\:\:16\:CO_2\
Dmitry [639]

Answer:

1.13×10^25 molecules of water.

Explanation:

Equation of the reaction;

C8H18(g) + 25/2 O2 (g) -------> 8CO2(g) + 9H2O(l)

It is important to first put down the balanced reaction equation. It is not possible to solve any problem on stoichiometric relationship without a balanced reaction equation. Once the equation is obtained, we can now proceed with other steps in the solution of the problem.

From the reaction equation, 1 mole of C8H18 produces 9 moles of water

1 mole of C8H18 occupies 22.4L volume while 1 mole of water contains 6.02×10^23 molecules of water

Hence

22.4 L of C8H18 produces 9(6.02×10^23) molecules of water

46.72 L of C8H18 will produce 46.72 L × 9(6.02×10^23) molecules of water/22.4 L

= 113×10^23 or 1.13×10^25 molecules of water.

5 0
3 years ago
Some hormones enter cells via
pochemuha
ANSWER: receptor-meditated endocytosis
I’m not sure if this is what you’re looking for but this is correct. Next time please add the full question and possible answers. HOPE this helps someone please leave thanks if so.
5 0
3 years ago
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7 0
3 years ago
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How many molecules are present in the following quantity<br> 0.250 mole of H2O
klio [65]
If  1mole ------------- is ---------------- 6.02*10²³
than 0.25mole ----- is ----------------  x

x = [0.25mole*6.02*10²³]/1mole = <u>1,505*10²³</u>
4 0
3 years ago
Dry ice is solid carbon dioxide. Instead of melting, solid carbon dioxide sublimes according to the following equation: CO2(s)→C
GREYUIT [131]

Answer:

m=8.79kg

Explanation:

First of all we need to calculate the heat that the water in the cooler is able to release:

Q=\rho * V*Cp*\Delta T

Where:

  • Cp is the mass heat capacity of water
  • V is the volume
  • \rho is the density

Q=1 g/cm^3 *15000 cm^3*4.184 \frac{J}{g*^{\circ}C}*(10-90)^{\circ}C

Q=-5020800 J=-5020.8 kJ

To calculate the mass of CO2 that sublimes:

-Q=\Delta H_{sub}*m

Knowing that the enthalpy of sublimation for the CO2 is: \Delta H_{sub}=571 kJ/kg

5020.8 kJ=571 kJ/kg*m

m=\frac{5020.8 kJ}{571 kJ/kg}=8.79kg

6 0
3 years ago
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