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ohaa [14]
3 years ago
15

HELP ASAP

Chemistry
1 answer:
Ghella [55]3 years ago
7 0

potassium reacts the most vigorously.

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Give the direction of the reaction, if K >> 1. Give the direction of the reaction, if K >> 1. The forward reaction i
anygoal [31]

Answer:

A. for K>>1 you can say that the reaction is nearly irreversible so the forward direction is favored. (Products formation)

B. When the temperature rises the equilibrium is going to change but to know how is going to change you have to take into account the kind of reaction. For endothermic reactions (the reverse reaction is favored) and for exothermic reactions (the forward reaction is favored)

Explanation:

A. The equilibrium constant K is defined as

K=\frac{Products}{reagents}

In any case  

aA +Bb  equilibrium Cd +dD

where K is:

K= \frac{[C]^{c}[D]^{d}}{[A]^{a}[B]^{b}}

[] is molar concentration.

If K>>> 1 it means that the molar concentration of products is a lot bigger that the molar concentration of reagents, so the forward reaction is favored.

B. The relation between K and temperature is given by the Van't Hoff equation

ln(\frac{K_{1}}{K_{2}})=\frac{-delta H^{o}}{R}*(\frac{1}{T_{1}}-\frac{1}{T_{2}})

Where: H is reaction enthalpy, R is the gas constant and T temperature.  

Clearing the equation for K_{2} we get:

K_{2}=\frac{K_{1}}{e^{\frac{-deltaH^{o}}{R}*(\frac{1}{T_{1}} -\frac{1}{T_{2}})}}

Here we can study two cases: when delta H^{o} is positive (exothermic reactions) and when is negative (endothermic reactions)

For exothermic reactions when we increase the temperature the denominator in the equation would have a negative exponent so K_{2} is greater that K_{1} and the forward reaction is favored.

When we have an endothermic reaction we will have a positive exponent so K_{2} will be less than K_{1} the forward reactions is not favored.  

{e^{\frac{-deltaH^{o}}{R}*(\frac{1}{T_{1}} -\frac{1}{T_{2}})}}

5 0
3 years ago
How do erosions affect land forms?
nata0808 [166]

Answer:

the anwser is landforms can be created by erosion

Explanation:

5 0
2 years ago
A. O CN<br> B. O NH4+<br> C. O s2-<br> D. O Cro 2-<br> Which of the following is an oxyanion?
ANEK [815]
C i think i got this off of usa test prep in class
5 0
3 years ago
I need help with number 5
pochemuha
The answer is package c because each cd would cost $1.87, which is the lowest price
7 0
2 years ago
Sakura tested the ph of several solutions. which substances are acidic? check all that apply. cola-flavored soda: 2.6 cranberry
Step2247 [10]

Answer:- Cola-flavored soda:2.6, cranberry juice:2.9 and pickle juice:5.5 are acidic.

Explanations:- As per the pH scale, the solution is acidic if the pH is below 7 and the solution is basic if the pH is above 7. The solution is neutral if the pH is exactly 7.

There are only three solutions with pH value below 7 and so they are acidic. these three solutions are, cola-flavored soda, cranberry juice and pickle juice.

Rest of them are basic as their pH value is greater than 7.

5 0
3 years ago
Read 2 more answers
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