Food metabolising inside of your liver.
The mass would be the sum of the protons and neutrons. Your answer would be 218
The volume (in liters) of CO₂ that can be consumed at STP by 435 g Na₂O₂ is 125 L of Co₂
<u><em>calculation</em></u>
2Na₂O₂(s) +2 CO₂ (g)→ 2 Na₂CO₃(s) + O₂(g)
Step 1 : find the moles of Na₂O₂
moles = mass÷ molar mass
from periodic table the molar mass of Na₂O₂ = (23 x2) +( 16 x2) = 78 g/mol
moles= 435 g÷ 78 g/mol = 5.58 moles
Step 2: use the mole ratio to determine the moles of CO₂
from given equation Na₂O₂ : CO₂ =2 :2 =1:1
Therefore the moles of CO₂ is also = 5.58 moles
Step 3: find the volume of CO₂ at STP
that is at STP 1 mole of a gas = 22.4 L
5.58 moles = ? l
<em>by cross multiplication</em>
= (5.58 moles x 22.4 L) / 1 mole = 125 L
Answer:
8.0 mol/L
Explanation:
To do this problem you need to use C₁V₁=C₂V₂. C=concentration and V=volume. (Note: you dont want to use M₁V₁=M₂V₂ because this is measuring mass not concentration).
So, V₁= 1.0L
C₂=2 Mol/L
V₂= 4 L
C₁ is unknown.
you would plug this equation in like this:
(C₁)(1.0 L)=(2.0 Mol/L)(4.0L).
Do algebra to get C₁ alone.
C₁=
The liters cancel out and you are left with mol/L or M
I hope this helps! good luck :)