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Alinara [238K]
3 years ago
6

Your chemistry lab partner is interested in studying how industrial chemicals can pollute the environment. What type of chemistr

y would you recommend to your lab partner and which courses should they take in order to study it? Explain your answer.​
Chemistry
1 answer:
Solnce55 [7]3 years ago
3 0

Answer:

I would recommend them becoming an Analytical Chemist because Analytical Chemists examine and identify various elements and compounds to find out the composition, structure, and nature of substances and they determine the concentration of chemical pollutants in soil, water,and air. I would recommend taking inorganic, organic, analytical, and physical chemistry as well as computer science, physics, and environmental science

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Example of a chemical change that you encounter everyday
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Food metabolising inside of your liver.
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What is the mass number of an atom that contains 85 protons 133 neutrons and 85 electrons​
Vikentia [17]
The mass would be the sum of the protons and neutrons. Your answer would be 218
6 0
3 years ago
Sodium peroxide (Na2O2) is used to remove carbon dioxide from (and add oxygen to) the air supply in spacecrafts. It works by rea
bazaltina [42]

 The volume  (in liters)  of CO₂  that can  be consumed at STP by 435 g Na₂O₂  is  125 L of Co₂

<u><em>calculation</em></u>

2Na₂O₂(s)  +2 CO₂ (g)→  2 Na₂CO₃(s)  + O₂(g)

Step 1 : find the moles  of Na₂O₂

moles = mass÷  molar mass

from periodic table the  molar mass  of Na₂O₂ = (23 x2) +( 16 x2) = 78 g/mol

 moles= 435 g÷ 78 g/mol = 5.58 moles

Step 2: use the mole ratio to determine the moles of CO₂

from given equation  Na₂O₂ : CO₂ =2 :2 =1:1

Therefore the  moles of CO₂  is also = 5.58 moles

Step 3: find the volume  of CO₂  at STP

that is at STP      1  mole of a gas = 22.4 L

                          5.58 moles = ? l

<em>by cross multiplication</em>

= (5.58 moles x 22.4 L) / 1 mole = 125 L

 

6 0
3 years ago
A 1 liter solution was diluted to a molarity of 2 M by bringing the volume up to 4 liters. What was the initial molarity of the
kompoz [17]

Answer:

8.0 mol/L

Explanation:

To do this problem you need to use C₁V₁=C₂V₂. C=concentration and V=volume. (Note: you dont want to use M₁V₁=M₂V₂ because this is measuring mass not concentration).

So, V₁= 1.0L

C₂=2 Mol/L

V₂= 4 L

C₁ is unknown.

you would plug this equation in like this:

(C₁)(1.0 L)=(2.0 Mol/L)(4.0L).

Do algebra to get C₁ alone.

C₁=\frac{(2.0 mol/L)(4.0L)}{1.0L} =8.0 mol/L

The liters cancel out and you are left with mol/L or M

I hope this helps! good luck :)

5 0
2 years ago
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