You could use a scale to measure the mass as well as a cup to hold the water. If you were comparing the two, you should also probably use a graduated cylinder to get the same amount of each type of water.
Hope this helped ^_^
The molecular mass of Carvone is calculated as;
= 12 (C)₁₀ + 1.008 (H)₁₄ + 16 (O)
= 120 + 14.112 + 16
= 150.112
%age of Carbon;
= (120 ÷ 150.112) × 100
= 79.94 %
%age of Hydrogen;
= (14.112 ÷ 150.112) × 100
= 9.40 %
%age of Oxygen;
= (16 ÷ 150.112) × 100
= 10.65 %
C table snap Lt it is a compound
The atomic weight of carbon dioxide is about 12.011 + 15.999 + 15.999 = 44.009.
44.009 grams of CO2 = 1 mole of CO2 CO2 = Carbon dioxide
25 ÷ 44.009 ≈ 0.568
About 0.568 moles of CO2
From Faraday's 1st law of electrolysis,
Total electricity passed into system = Q = IT = 250 X 24 X 60 X 60
= 2.16 X 10^7 C
We know that, 96500 C = 1 F
∴ 2.16 X 10^7 C = <span>223.8 F
</span>
Now, number of moles of<span> MnO2 deposited = 223.8/2=111.9
</span>
Finally, 1 mole of MnO2 ≡ 86.94 g
∴ 111.9 mole of MnO2 ≡ 111.9 X 86.94 = 9728 g
Thus, <span>mass of MnO2 that will be deposited at anode = 9728 g</span>
