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Viefleur [7K]
3 years ago
11

Using your knowledge of chemistry and the information in Reference Table H, which statement concerning propanone and water at 50

°C is true?(1) Propanone has a higher vapor pressure and stronger intermolecular forces than water.(2) Propanone has a higher vapor pressure and weaker intermolecular forces than water.(3) Propanone has a lower vapor pressure and stronger intermolecular forces than water.(4) Propanone has a lower vapor pressure and weaker intermolecular forces than water.
Chemistry
1 answer:
stiv31 [10]3 years ago
3 0
The answer is (2) higher vapor pressure and weaker intermolecular forces. Propanone has a lower boiling point, so it is more volatile than water. Propanone's vapor pressure is, therefore, higher than that of water at 50 degrees Celsius. Propanone is more volatile due to the fact that the intermolecular forces that hold its molecuels together are not as strong as those that hold together molecules of water. Since the IMFs are weaker, it takes less thermal energy to break individual molecules free of each other.
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What is the sequence of coefficients that will balance the following decomposition reaction of dihydrogen monosulfide? H₂S ----&
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Answer:

Explanation:

The law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

Then, you must balance the chemical equation. For that, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts.  

The coefficients located in front of each molecule indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts.

By multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction.

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Right side: 2 H and 8 S

In this case you must start balancing the sulfur to have 8 on each side of the reaction. So:

8 H₂S → H₂ + S₈

Now the amount of elements on each side of the equation:

Left side: 16 H and 8  

Right side: 2 H and 8 S

Now you need to start balancing the hydrogen to get the same amount from each side of the reaction. So:

8 H₂S → 8 H₂ + S₈

Now the amount of elements on each side of the equation:

Left side: 16 H and 8  

Right side: 16 H and 8 S

<u><em>The balanced reaction is:</em></u>

<u><em>8 H₂S → 8 H₂ + S₈</em></u>

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