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Viefleur [7K]
3 years ago
11

Using your knowledge of chemistry and the information in Reference Table H, which statement concerning propanone and water at 50

°C is true?(1) Propanone has a higher vapor pressure and stronger intermolecular forces than water.(2) Propanone has a higher vapor pressure and weaker intermolecular forces than water.(3) Propanone has a lower vapor pressure and stronger intermolecular forces than water.(4) Propanone has a lower vapor pressure and weaker intermolecular forces than water.
Chemistry
1 answer:
stiv31 [10]3 years ago
3 0
The answer is (2) higher vapor pressure and weaker intermolecular forces. Propanone has a lower boiling point, so it is more volatile than water. Propanone's vapor pressure is, therefore, higher than that of water at 50 degrees Celsius. Propanone is more volatile due to the fact that the intermolecular forces that hold its molecuels together are not as strong as those that hold together molecules of water. Since the IMFs are weaker, it takes less thermal energy to break individual molecules free of each other.
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26.7% is the percent composition by mass of sulfur in a compound named magnesium sulfate. Explanation: Molar mass of compound = 120 g/mol.

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2 years ago
Indicate the correct number of sig figs
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Explanation:

The answer to questions are

A) 4

B) 3

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What will the pressure be if 89.9 moles of argon are contained in a 12.0 L cylinder that is pressurized at a temperature of 300
irinina [24]
  • P=nRT/V
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2 years ago
A certain metal M crystallizes in a lattice described by a body-centered cubic (bcc) unit cell. The lattice constant (a, the edg
Furkat [3]

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radius = 156 pm

Explanation:

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r=a\sqrt{3}/4

Given

a = 360 pm

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3 0
3 years ago
If 1,079.75 Joules of heat are added to 77.75 grams of water, by how many degrees Celsius would the water increase? Assume water
djyliett [7]

Answer:

If 1,079.75 Joules of heat are added to 77.75 grams of water, by 3.32 degrees Celsius the temperature of  water will increase

\Delta T=3.32 C^{0}

Explanation:

q = mC\Delta T

Here , q = heat added / removed from the substance

m  = mass of the substance taken

\Delta T = Change in temperature

C = specific heat capacity of the substance

In liquid state the value of C for water is :

4.18 J/gC^{0}

Given values :

q = 1079.75 J

m = 77.75 gram

Insert the value of C, m , q in the given equation

q = mC\Delta T

on transposing ,

\Delta T=\frac{q}{mC}

\Delta T=\frac{1079.75}{77.75\times 4.18}

\Delta T=3.32 C^{0}

3 0
3 years ago
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