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podryga [215]
3 years ago
10

A college student has just bought a small computer that weighs 50N. Her apartment is on the 5th floor which is 35 meters up. How

much work must she do to drag her computer up the stairs?​
Physics
1 answer:
Vladimir79 [104]3 years ago
4 0

Answer:

W = 1750 J

Explanation:

It is given that,

Weight of a computer, F = 50 N

A student wants to keep it on the 5th floor which is 35 meters up.

We need to find the work done by her to drag her computer up the stairs. Let it is W. Using the formula of work as follows :

W = F d

Put all the values,

W = 50 N × 35 m

W = 1750 J

So, 1750 J of work is done by her to drag the computer up the stairs.

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nalin [4]

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3 years ago
A pendulum consists of a 2.7 kg stone swinging on a 4.0 m string of negligible mass. The stone has a speed of 8.1 m/s when it pa
Brut [27]

Answer:

a). v=4.77 \frac{m}{s}

b). β=80.61

c). E=88.5J

Explanation:

a).

m1=2.7 kg\\L=4m\\v_{1}=8.1 \frac{m}{s}\\\beta=63

\frac{m*v_{1} ^{2} }{2}+m*g*y_{1}=\frac{m*v_{2}^{2} }{2}+m*g*y_{2}\\\frac{m*v_{1} ^{2} }{2}=\frac{m*v_{2}^{2} }{2}+m*g*y_{2}\\v_{2}=\sqrt{v_{1}^{2}-2*g*y_{2}}\\y_{2} =L-L*cos(\beta)\\v_{2}=\sqrt{v_{1}^{2}-2*g*(L-L*cos(\beta))}\\v_{2}=\sqrt{8.1^{2}-2*9.8*(4(1-*cos(63))}\\v_{2}=\sqrt{8.1^{2}-42.8}\\v_{2}=\sqrt{64-42.8}\\v_{2}=\sqrt{21.19}=4.77 \frac{m}{s}

b).

\frac{m*v_{1}^{2}}{2} +m*y_{1} =\frac{m*v_{2}^{2}}{2} +m*y_{2}\\\frac{m*v_{1}^{2}}{2} +0 =0 +m*y_{2}\\y_{2}=\frac{v_{1}^{2}}{2*g}=\frac{(8.1^\frac{m}{s}){2}}{2*9.8\frac{m}{s^{2} }}=3.34 m\\ 3.34m=L(1-cos(\alpha)\\3.34m=4*(1-cos(\alpha ))\\cos(\alpha )=\frac{4-3.34}{4}=0.16\\(\alpha )= cos^{-1}*(0.163)\\ (\alpha )= 80.61

c).

E=\frac{m*v_{1} ^{2} }{2}\\ E=\frac{(2.7kg)*(8.1\frac{m}{s})^{2}}{2}=\frac{177.147\frac{kg*m^{2}}{s^{2}}}{2}\\\\E=88.5 J

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