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podryga [215]
3 years ago
10

A college student has just bought a small computer that weighs 50N. Her apartment is on the 5th floor which is 35 meters up. How

much work must she do to drag her computer up the stairs?​
Physics
1 answer:
Vladimir79 [104]3 years ago
4 0

Answer:

W = 1750 J

Explanation:

It is given that,

Weight of a computer, F = 50 N

A student wants to keep it on the 5th floor which is 35 meters up.

We need to find the work done by her to drag her computer up the stairs. Let it is W. Using the formula of work as follows :

W = F d

Put all the values,

W = 50 N × 35 m

W = 1750 J

So, 1750 J of work is done by her to drag the computer up the stairs.

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Distinguish between elastic collasin<br>and inelastic collasin<br>​
skelet666 [1.2K]

Explanation:

In an elastic collision, two or more bodies are in contact with one another and there is no net loss of kinetic energy in the system. By the virtue of this, the bodies and objects do not stick together after they collide.

Both momentum and kinetic energy are conserved in an elastic collision. An example is when a football hits a wall.

For an inelastic collision, the bodies sticks together after they collide and there is a loss of kinetic energy after they collide. An example of this type of collision is when a gum is throw against a wall.

3 0
3 years ago
A motorcycle is following a car that is traveling at a constant speed on a straight highway. Initially, the car and the motorcyc
Artist 52 [7]

Answer:

(a) 3.807 s

(b) 145.581 m

Explanation:

Let Δt = t2 - t1 be the time it takes from the moment when the motorcycle starts to accelerate until it catches up with the car. We know that before the acceleration, both vehicles are travelling at a constant speed. So they would maintain a distance of 58 m prior to the acceleration.

The distance traveled by car after Δt (seconds) at v_c = 23m/s speed is

s_c = \Delta t v_c = 23\Delta t

The distance traveled by the motorcycle after Δt (seconds) at m_m = 23 m/s speed and acceleration of a = 8 m/s2 is

s_m = \Delta t v_m + a\Delta t^2/2

s_m = 23\Delta t + 8\Delta t^2/2 = 23 \Delta t + 4 \Delta t^2

We know that the motorcycle catches up to the car after Δt, so it must have covered the distance that the car travels, plus their initial distance:

s_m = s_c + 58

23 \Delta t + 4 \Delta t^2 = 23\Delta t + 58

4 \Delta t^2 = 58

\Delta t^2 = 14.5

\Delta t = \sqrt{14.5} = 3.807s

(b)

s_m = 23 \Delta t + 4 \Delta t^2

s_m = 23*3.807 + 58 = 145.581 m

5 0
3 years ago
The speed of a bus increases uniformly from 15meter per seconds to 60 meter per seconds in 20second.Calculate, the acceleration.
Anarel [89]

Answer:

2.25 m/s²

Explanation:

Acceleration = change in velocity / time taken

                     = (60-15)/20

                     = 2.25 m/s²

6 0
4 years ago
The acceleration of The Munster’s car is 9.71 m/s2 when he applies 5050 N of net force (by way of the engine). What is the mass
Ainat [17]

Given that,

Acceleration, a = 9.71 m/s²

Force, F = 5050 N

mass, m = ?

Since, we know that

F=ma

m= F/a

m= 5050/9.71

m= 520.08 kg

The mass of hi car is 520.08 kilograms.

4 0
3 years ago
Why does a bowling ball and a father fall at the same speed while in a vacuum? <br> PLZ NEED HELP
k0ka [10]

Answer:

there is no drag in a vacuum (why is father in a vaccum)

Explanation:

there is nothing to hit and slow the object other than gravity like dust or air

6 0
3 years ago
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