Seca(1-sina)(seca+tana)=1
Left hand side
=(1-sina) (seca +tana) / cosa
=seca +tana - sinaseca - sinatan / cosa
=seca + tana -tana -(sin^2a/cosa) / cosa
=(1/cosa - sin^2a/cosa) / cosa
= (1-sin^2a / cosa) / cosa
= (1-sin^2a)/ (cos^2a)
=1 (verified)
The answer would be -6n+2mn-25pn
Answer: 25 tables.
Step-by-step explanation:
5 • 10*2= 500 (10*2= 100, then 100 times 5)
2 • 10*1= 20 (10*1= 10, then times 2)
Therefore a cafeteria can seat 500 students. Each table had 20 seats.
Divide 500/20 and get 25.
Hope this helps
If you mean greatest common factor then that means
factor each and group the ones that are same
81=3 times 3 times 3 times 3
108=2 times 2 times 3 times 3 times 3
117=3 times 3 times 13
so we look for the group common to all (I bolded it)
81=3 times 3 times 3 times 3
108=2 times 2 times 3 times 3 times 3
117=3 times 3 times 13
the answeis 3 times 3=9
greates common denomenator of these nubers is 9
