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Vikki [24]
3 years ago
7

Use the nuclear decay reaction in the picture to answer the following question.

Chemistry
1 answer:
allsm [11]3 years ago
5 0

Answer:

1a. Both sides of the decay reaction have the same charge.

b. The number of nucleons on both sides are the same.

2. The binding energy of one mole of the atom is 17.172 × 10^{16} J.

Explanation:

1a. Considering the two sides of the decay reaction and with respect to the law of conservation of charge, it can be observed that both sides have the same charge. Charge can not be created or destroyed in the process.

b. The number of nucleons on both sides are equal. No nucleon is created or destroyed in the process.

2. Binding energy is the minimum energy required to separate an atom into its nucleons. From Einstein's energy equation;

             E = Δmc^{2}

Where E is the binding energy of the atom, Δm is the mass defect and c is the speed of light.

Given that: Δm = 1.908 g/mol and c = 3 × 10^{8}. So that:

           E = 1.908 × (3*10^{8}) ^{2}

              = 1.908 × 9 × 10^{16}

              = 17.172 × 10^{16} J

The binding energy of one mole of the atom is 17.172 × 10^{16} J.

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Answer:

маликулярная масса ровна  23

8 0
3 years ago
In calculating the equilibrium constant for a reaction, the coefficients of the chemical equation are used as exponents for the
BartSMP [9]

Answer: The given statement is TRUE.

Explanation:

An equilibrium reaction is one in which rate of forward reaction is equal to the rate of backward reaction.

Equilibrium constant is defined as the ratio of the product of the concentration of products to the product of the concentration of reactants each raised to their stochiometric coefficient.

For example for the given equilibrium reaction;

2H_2O(g)\leftrightharpoons 2H_2(g)+O_2(g)

K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}

Thus the given statement that in calculating the equilibrium constant for a reaction, the coefficients of the chemical equation are used as exponents for the factors in the equilibrium expression is True.

7 0
3 years ago
Draw a mechanism for the first step of the reaction between methyllithium (CH3Li) and acetone. Then answer the two multiple choi
pogonyaev

Answer:

See the attached image

Explanation:

The first step is the production of the <u>carboanion</u> in the CH_3Li compound. We will get the <u>negative charge</u> on the methyl group and the <u>positive charge</u> in the Li atom.

Then the carboanion can <u>attack the acetone</u>. The double bond of the oxo group would <u>delocalized</u> upon the oxygen, generating a positive charge in the carbon that can be attacked by the carboanion formaiting a <u>new C-C bond</u>.

8 0
3 years ago
Calculate the average molar bond enthalpy of the carbon-hydrogen bond in a ch4 molecule.
balandron [24]
<span>The average molar bond enthalpy of the carbon-hydrogen bond in a CH4 molecule is 416 KJ/mol. (+716.7 + (4 x 218) - (- 74.6) ) / 4 = + 1663.3 / 4 = 416</span>
7 0
3 years ago
Read 2 more answers
The average score for games played in the NFL is 21.1 and the standard deviation is 8.9 points. 46 games are randomly selected.
kaheart [24]

Answer:

A) P(21.4317 < ¯x < 22.7561) = 0.2975

B) Q1 for the ¯x distribution = 21.9844

Explanation:

The Central Limit theorem allows us to say that

Sample mean = Population mean = 21.1 points

Mean of sampling distribution = σₓ = (σ/√n)

σ = population standard deviation = 8.9 points

n = sample size = 46

σₓ = (8.9/√46) = 1.3122334098 = 1.3122

A) P(21.4317 < ¯x < 22.7561) =

This is a normal distribution problem

To find this probability, we will use the normal probability tables

We first normalize/standardize 21.4317 and 22.7561.

The standardized score of any value is that value minus the mean divided by the standard deviation.

For 21.4317

z = (x - μ)/σ = (21.4317 - 21.1)/1.3122 = 0.25

For 22.7561

z = (x - μ)/σ = (22.7561 - 21.1)/1.3122 = 1.26

The required probability

P(21.4317 < ¯x < 22.7561) = P(0.25 < z < 1.26)

Checking the tables

P(21.4317 < ¯x < 22.7561) = P(0.25 < z < 1.26)

= P(z < 1.26) - P(z < 0.25)

= 0.89617 - 0.59871

= 0.29746 = 0.2975 to 4 d.p.

B) Q1 for the distribution is the first quartile. The first quartile is greater than 25% of the distribution.

P(x > Q1) = 0.25

Let the z-score that corresponds to Q1 be z'

P(x > Q1) = P(z > z') = 0.25

But P(z > z') = 1 - P(z ≤ z') = 0.25

P(z ≤ z') = 1 - 0.25 = 0.75

From the normal distribution tables,

z' = 0.674

z' = (Q1 - μ)/σ

0.674 = (Q1 - 21.1)/1.3122

Q1 = 0.674×1.3122 + 21.1 = 21.9844228 = 21.9844 to 4 d.p.

Hope this Helps!!!

7 0
3 years ago
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