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solong [7]
3 years ago
15

Help me out please:)

Mathematics
1 answer:
NikAS [45]3 years ago
7 0

Answer:

for both q I think is 12.5% but Im not that sure I'm sorry

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A landscape architect wished to enclose a rectangular garden on one side by a brick wall costing $20/ft and on the other three s
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Answer:

The dimensions of the garden that minimize the cost is 9.018 feet(length) and 13.528 feet(width)

Step-by-step explanation:

Let the length of garden be x

Let the breadth of garden be y

Area of Rectangular garden = Length \times Breadth = xy

We are given that the area of the garden is 122 square feet

So, xy=122 ---A

A landscape architect wished to enclose a rectangular garden on one side by a brick wall costing $20/ft

So, cost of brick along length x = 20 x

On the other three sides by a metal fence costing $10/ft.

So, Other three side s = x+2y

So, cost of brick along the other three sides= 10(x+2y)

So, Total cost = 20x+10(x+2y)=20x+10x+20y=30x+20y

Total cost = 30x+20y

Substitute the value of y from A

Total cost = 30x+20(\frac{122}{x})

Total cost = \frac{2440}{x}+30x

Now take the derivative to minimize the cost

f(x)=\frac{2440}{x}+30x

f'(x)=-\frac{2440}{x^2}+30

Equate it equal to 0

0=-\frac{2440}{x^2}+30

\frac{2440}{x^2}=30

\sqrt{\frac{2440}{30}}=x

9.018 =x

Now check whether it is minimum or not

take second derivative

f'(x)=-\frac{2440}{x^2}+30

f''(x)=-(-2)\frac{2440}{x^3}

Substitute the value of x

f''(x)=-(-2)\frac{2440}{(9.018)^3}

f''(x)=6.6540

Since it is positive ,So the x is minimum

Now find y

Substitute the value of x in A

(9.018)y=122

y=\frac{122}{9.018}

y=13.528

Hence the dimensions of the garden that minimize the cost is 9.018 feet(length) and 13.528 feet(width)

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Answer:

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Solve 4X^2+7 = 8X +4 by using the quadratic formula
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Answer:

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