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Mkey [24]
3 years ago
15

A 15.0 g piece of graphite is heated to 100.0°C and placed in a calorimeter. The

Chemistry
2 answers:
never [62]3 years ago
7 0

Answer:

?a e i o iqjfjcjskskxkckbkv

LenKa [72]3 years ago
4 0

Answer:

0.714Jg^-10C^-1.

Explanation:

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C Fossil fuels will run out soon

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Add the polynomials (7x^3-2x^2-12)+(3x^3-8x^2+10x)
laiz [17]

Answer:

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Explanation:

4 0
2 years ago
If an object has a volume of 2 millimeters and a mass of 10 grams, calculate the density of the object. (4 points)
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3 0
3 years ago
This is the balances equations. C3H8 + 5O2 → 3CO2 + 4H2O How many moles of oxygen are required to produce 37.15 g CO2
AleksandrR [38]
Molar mass O2 = 31.99 g/mol

Molar mass CO2 = 44.01 g/mol

Moles ratio:

<span>C3H8 + 5 O2 = 3 CO2 + 4 H2O 
</span>
5 x 44.01 g O2 ---------------- 3 x 44.01 g CO2
( mass of O2) ------------------ 37.15 g CO2

mass of O2 = 37.15 x 5 x 44.01/ 3 x 44.01

mass of O2 = 8174.8575 / 132.03

mass of O2 = 61.916 g 

Therefore:

1 mole O2 ----------------- 31.99 g
moles O2 -------------------- 61.916

moles O2 = 61.916 x 1 / 31.99

moles = 61.916 / 31.99 => 1.935 moles of O2
4 0
3 years ago
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