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aksik [14]
3 years ago
12

What is the percent yield of a reaction in which 200. g of phosphorus trichloride reacts with excess water to form 91.0 g of hcl

and aqueous phosphorous acid (h3po3)?
Chemistry
2 answers:
Snowcat [4.5K]3 years ago
4 0
Answer is: <span>yield of a reaction is 56,4%.
</span>Chemical reaction: PCl₃ + 3H₂O → 3HCl + H₃PO₃.
m(PCl₃) = 200 g.
m(HCl) = 91,0 g.
n(PCl₃) = m(PCl₃) ÷ M(PCl₃).
n(PCl₃) = 200 g ÷ 137,33 g/mol.
n(PCl₃) = 1,46 mol.
n(HCl) = m(HCl) ÷ M(HCl).
n(HCl) = 91 g ÷ 36,45 g/mol.
n(HCl) = 2,47 mol.
From reaction: n(PCl₃) : n(HCl) = 1 : 3.
n(HCl) = 1,46 mol · 3 = 4,38 mol.
Yield of reaction: 2,47 mol ÷ 4,38 mol · 100% = 56,4%.
myrzilka [38]3 years ago
3 0

<u>Answer:</u> The percent yield of the reaction is 56.92 %.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

Given mass of phosphorus trichloride = 200 g

Molar mass of phosphorus trichloride = 137.33 g/mol

Putting values in equation 1, we get:

\text{Moles of phosphorus trichloride}=\frac{200g}{137.33g/mol}=1.46mol

The chemical reaction of phosphorus trichloride with water follows the equation:

PCl_3+3H_2O\rightarrow H_3PO_3+3HCl

As, water is present in excess. It is considered as excess reagent.

Phosphorus trichloride is considered as a limiting reagent because it limits the formation of product.

By stoichiometry of the reaction:

1 mole of phosphorus trichloride produces 3 moles of hydrochloric acid.

So, 1.46 moles of phosphorus trichloride will produce = \frac{3}{1}\times 1.46=4.38mol of hydrochloric acid.

  • Now, calculating the mass of hydrochloric acid from equation 1, we get:

Molar mass of hydrochloric acid = 36.5 g/mol

Moles of hydrochloric acid = 4.38 moles

Putting values in equation 1, we get:

4.38mol=\frac{\text{Mass of hydrochloric acid}}{36.5g/mol}\\\\\text{Mass of hydrochloric acid}=159.87g

  • To calculate the percentage yield of hydrochloric acid, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of hydrochloric acid = 91.0 g

Theoretical yield of hydrochloric acid = 159.87 g

Putting values in above equation, we get:

\%\text{ yield of hydrochloric acid}=\frac{91.0g}{159.87g}\times 100\\\\\% \text{yield of hydrochloric acid}=56.92\%

Hence, the percent yield of the reaction is 56.92 %.

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A student prepared a stock solution by dissolving 10.0 g of KOH in enough water to make 150. mL of solution. She then took 15.0
yanalaym [24]

Answer: The concentration of KOH for the final solution is 0.275 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute

 V_s = volume of solution in ml = 150 ml

moles of solute =\frac{\text {given mass}}{\text {molar mass}}=\frac{10.0g}{56g/mol}=0.178moles

Now put all the given values in the formula of molality, we get

Molality=\frac{0.178\times 1000}{150}=1.19M

According to the dilution law,

C_1V_1=C_2V_2

where,

C_1 = molarity of stock solution = 1.19 M

V_1 = volume of stock solution = 15.0 ml

C_2 = molarity of diluted solution = ?

V_2 = volume of diluted solution = 65.0 ml

Putting in the values we get:

1.19\times 15.0=M_2\times 65.0

M_1=0.275M

Therefore, the concentration of KOH for the final solution is 0.275 M

5 0
2 years ago
What is the minimum amount of 6.0 M H2SO4H2SO4 necessary to produce 25.0 g of H2(g)H2(g) according to the reaction between alumi
Lelechka [254]

2.083 Liters of 6.0 M solution sulfuric acid is required. This solved using molecular calculations and Titration.

Solution: 2Al(s)+3H_2SO_4(aq) = Al_2(SO_4)_3(aq)+3H_2(g)

Moles of hydrogen gas =  \frac{25}{2} = 12.5 mol

Then 12.5 moles of hydrogen will be obtained from Moles of Sulfuric acid = 12.5 mol

Molarity of the sulfuric acid solution = 6.0 M = 6 mol/ l

6M = \frac{12.5 mole}{V}

where V is the volume needed

V = \frac{12.5}{6}

V = 2.083 l

<h3>What is Titration?</h3>
  • Titration, commonly referred to as titrimetry, is a typical quantitative chemical analysis method used in laboratories to ascertain the unidentified quantity of an analyte .
  • Titration is frequently referred to as volumetric analysis because it relies heavily on volume measurements. The titrant or titrator is a reagent that is prepared as a standard solution.
  • To determine concentration, a solution of the analyte or titrand reacts with a known concentration and volume of the titrant. The titration volume is the amount of titrant that has responded.
  • Titrations come in a variety of forms with various protocols and objectives. Redox and acid-base titrations are the two most typical types of qualitative titrations.

To learn more about titration with the given link

brainly.com/question/2728613

#SPJ4

8 0
2 years ago
6. Identify the number of neutrons in one atom of silicon with an isotopic mass number of 28 amu.
Sholpan [36]

14

Explanation:

The number of neutrons in one atom of silicon with an isotopic mass number of 28amu is 14.

An atom is made up three fundamental sub-atomic particles which are:

  Protons, neutron and electrons

Protons are the positively charged particles in an atom

Neutrons do not carry any charges

Electrons are the negatively charged particles.

In the nucleus of an atom, both protons and neutrons can be found. They are the massive particle in an atom.

  The mass number of an atom = number of protons + number of neutrons

Number of neutrons = mass number - number of protons.

From the periodic table, we know that silicon has an atomic number of 14.

The atomic number is the number of protons in an atom:

         Number of neutrons = 28 - 14 = 14amu

In the atom, we will have 14amu of neutrons in a silicon atom.

learn more:

Number of neutrons brainly.com/question/2757829

#learnwithBrainly

5 0
3 years ago
Please answer fast, I will give brainliest if correct!
gizmo_the_mogwai [7]

Answer:

Explanation: 30 min

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