<u>Answer:</u> The percent yield of the reaction is 56.92 %.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of phosphorus trichloride = 200 g
Molar mass of phosphorus trichloride = 137.33 g/mol
Putting values in equation 1, we get:

The chemical reaction of phosphorus trichloride with water follows the equation:

As, water is present in excess. It is considered as excess reagent.
Phosphorus trichloride is considered as a limiting reagent because it limits the formation of product.
By stoichiometry of the reaction:
1 mole of phosphorus trichloride produces 3 moles of hydrochloric acid.
So, 1.46 moles of phosphorus trichloride will produce =
of hydrochloric acid.
- Now, calculating the mass of hydrochloric acid from equation 1, we get:
Molar mass of hydrochloric acid = 36.5 g/mol
Moles of hydrochloric acid = 4.38 moles
Putting values in equation 1, we get:

- To calculate the percentage yield of hydrochloric acid, we use the equation:

Experimental yield of hydrochloric acid = 91.0 g
Theoretical yield of hydrochloric acid = 159.87 g
Putting values in above equation, we get:

Hence, the percent yield of the reaction is 56.92 %.