Answer:
1.5x10²² particulates
Explanation:
Assuming ideal behaviour, we can solve this problem by using the <em>PV=nRT </em>formula, where:
- V = 250 mL ⇒ 250 / 1000 = 0.250 L
- R = 0.082 atm·L·mol⁻¹·K⁻¹
- T = 15 °C ⇒ 15 + 273 = 288 K
We <u>input the given data</u>:
- 2.4 atm * 0.250 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 288 K
And <u>solve for n</u>:
Finally we <u>calculate how many particulates are there in 0.025 moles</u>, using <em>Avogadro's number</em>:
- 0.025 mol * 6.023x10²³ particulates/mol = 1.5x10²² particulates
Answer:
9 orbits, The 3d subshell will be having 5 orbitals. On adding all the orbitals of 3s, 3p and 3d we get a total of 9 orbitals. Therefore, there are 9 orbitals in the third shell.
Answer:
Using radiometric dating they SUPPORT the hypothesis on the origin of life on Earth
Explanation:
A fossil is a preserved remnant of a living organism from the past, this fossilization can be achieved by many processes including carbonization, recrystallization, permineralization, etc. These fossils can be used to obtain different information about the past and the origin of life on earth, for example,<em> chemical fossils are a kind of fossil found in rocks and fuels like coal or petroleum, they represent one of the oldest kind of fossils found and through the use of radiometric dating, where carbon isotopes are measured, their existence implies the presence of life as early as 4.1 billion years ago.</em>
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The options in the question are:
a) +0.46 V
b) +0.617 V
c) +1.39 V
d) -0.46 V
e) +1.21 V
Answer:
b) +0.617 V
Explanation:
The equation shows that the anode is Sn2+/Sn4+ while the cathode is Fe3+/Fe2+.
The E° cell is obtained from E°cathode - E°Anode
E°cathode= 0.154V
E°Anode= 0.771V
E° cell= E°cathode - E°Anode= 0.771-0.154=0.617
