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Answer:
8.75 g of ZnO
Solution:
The Balance Chemical Reaction is as follow,
2 ZnS + 3 O₂ → 2 ZnO + 2 SO₂
Step 1: Find out the limiting reagent as;
According to Equation ,
194.94 g (2 mole) ZnS reacts with = 96 g (3 moles) of O₂
So,
12.85 g of ZnS will react with = X g of O₂
Solving for X,
X = (12.85 g × 96 g) ÷ 194.94 g
X = 6.32 g of O₂
It means for total utilization of 12.85 g of ZnS we require 6.32 g of O₂, but we are provided with 15.91 g of O₂. Therefore, ZnS is the limiting reagent and will control the yield.
Step 2: Calculate Amount of ZnO produced as;
According to Equation ,
194.94 g (2 mole) ZnS produces = 132.81 g (2 moles) of ZnO
So,
12.85 g of ZnS will produce = X g of ZnO
Solving for X,
X = (12.85 g × 132.81 g) ÷ 194.94 g
X = 8.75 g of ZnO
Enzyme Substrate Products
Lipase Lipid Glycerol + Fatty Acid
Enzyme Substrate Products
Pepsin Protein Peptides + Amino Acids
Trypsin Protein Peptides + Amino Acids
