The answer is D. Michael Faraday
Answer:
![P=58.3kW](https://tex.z-dn.net/?f=P%3D58.3kW)
Explanation:
Given data
Length L=2.5 m
Radius R=d/2=30/2 = 15 mm
Torque based on allowable stress
Allowable shear stress τ=50 Mpa
Allowable torque T=(π/2)τc³
![T=\frac{\pi }{2}(50*10^{6} )(0.015)^{3} \\ T=264.94N.m](https://tex.z-dn.net/?f=T%3D%5Cfrac%7B%5Cpi%20%7D%7B2%7D%2850%2A10%5E%7B6%7D%20%29%280.015%29%5E%7B3%7D%20%5C%5C%20T%3D264.94N.m)
Torque based on allowable angle of twist
Allowable Angle of twist
Ф=7.5°
Ф=7.5×(π/180)=130.90×10⁻³ rad
Allowable torque
T=(GJФ)/L
T=(G(π/2)c⁴)Ф)/L
T=(πGc⁴Ф)/2
![T=\frac{\pi (77.2*10^{9} )(0.015)^{4}(130.90*10^{-3} ) }{2}\\ T=265.07N.m](https://tex.z-dn.net/?f=T%3D%5Cfrac%7B%5Cpi%20%2877.2%2A10%5E%7B9%7D%20%29%280.015%29%5E%7B4%7D%28130.90%2A10%5E%7B-3%7D%20%29%20%7D%7B2%7D%5C%5C%20T%3D265.07N.m)
Maximum Power Transmitted
Maximum power transmitted is given by
![P=2\pi fT\\P=2\pi (35)(265.07)\\P=58262.386watt\\P=58.3kW](https://tex.z-dn.net/?f=P%3D2%5Cpi%20fT%5C%5CP%3D2%5Cpi%20%2835%29%28265.07%29%5C%5CP%3D58262.386watt%5C%5CP%3D58.3kW)
Do you have choices like a b c d and i can help