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lubasha [3.4K]
3 years ago
7

You launch a model rocket that has a mass of 1.5 kg. At a height of 300 m, it is traveling at 125 m/s. What is it's kinetic ener

gy at this point
Physics
1 answer:
Komok [63]3 years ago
5 0

Answer:

KE = 11,719 J

Explanation:

KE = ½ mv²

KE = ½ (1.5 kg) (125 m/s)²

KE = 11,719 J

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tamaranim1 [39]

Answer:

Explanation:

A 40kg child throw stone of 0.5kg

At a direction of 5m/s

Recoil can be calculated using recoil of a gun formula

m_1•v_1 + m_2•v_2

m_1•v_1 = -m_2•v_2

The negative sign show that the momentum of the boy is directed oppositely to that of the stone

m_1 Is mass of boy

v_1 is the recoil velocity of the boy

m_2 is mass of stone

v_2 is the velocity of stone

Then,

m_1•v_1 = -m_2•v_2

40•v_1 = -0.5 × 5

40•v_1 = -2.5

v_1 = -2.5 / 40

v_1 = -0.0625 m/s

The recoil velocity of the boy is 0.0625 m/s

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Firdavs [7]

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7 0
3 years ago
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Answer:

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