Answer:
c.The value of T at Recording Station N would be greater than T at Recording Station S.
Explanation:
We can deduce from the information provided that the value of T at recording station N would be greater than T at recording station S.
This problem relates distance with time.
Speed = 
Distance = Speed x time
- Just like any other physical quantity, speed of a substance is directly related to time.
- The larger the time taken the farther the distance it will cover assuming the velocity is constant.
- Earthquake waves for example moves at constant speed with a unique velocity in earth materials.
- The farther the distance, the more time it will take to reach the seismic recording station.
- Since N is a distance of 200km from the epicenter, it will take a greater time and have a higher reading of T to reach the station.
Answer:
163.94
Explanation:
Na = 22.99 (3)
P = 30.97
O = 16.00 (4)
22.99(3) + 30.97 +16.00(4) = 163.94
Hope that helps
Answer:
23.27 L
Explanation:
The balanced reaction of ammonia and nitrogen monoxide is shown below as:
4NH₃(g) + 6NO(g) ⇒ 5N₂(g) + 6H₂O(l)
Given that:
Volume of nitrogen monoxide = 34.9 L
Since, temperature and pressure are same, volume coefficients would be same as equation coefficients.
So,
6 L of nitrogen monoxide reacts with 4 L of ammonia.
1 L of nitrogen monoxide reacts with 4/6 L of ammonia.
34.9 L of nitrogen monoxide reacts with (4/6)*34.9 L of ammonia.
Amount of ammonia required = 23.27 L
Answer:2-liver because it doesnt belong to digestive system
3-esophagus because it doesnt belong to the circulatory system
4-heart because it doesnt belong to the nervous system
5-skull because it doesnt belong to the endocrine system
Explanation:
1.5 % is the percent yield in the reaction.
Explanation:
Given that:
original mass of the sample used in reaction = 1.897 grams
product formed after decomposition = 1.071 grams
The reaction for the decomposition:
Mg(HCO3)2 (s) ⇒ CO2 (g) + H2O (g) + MgCO2 (s)
It says that 1 mole of Mg(HCO3)2 yielded 1 mole of MgCO2 on decomposition
68.31 grams/mole or 68.31 grams of MgCO2 is formed
percent yield = 
x 100
putting the values in the equation:
percent yield = 
= 0.015 x100
PERCENT YIELD = 1.5 %
