All categories

3 years ago

Heeelllllllllllllpppppppppp

Chemistry

1 answer:

klio [65]3 years ago

5 0

It looks to me the answer would be C or D since the covalent bond is the sharing of electron pairs between atoms. Those are the only two that talk about the share of the bond of the electrons.

You might be interested in

Drag each tile to the correct image. Match each hydrocarbon class to its structure. carboxylic acid amine halocarbon alcohol

Sonja [21]

Answer:

1. Amine.

2. Alcohol.

3. Carboxylic Acid.

4. Halocarbon.

Explanation:

3 0

3 years ago

Compounds in a and b were named incorrectly. On a sheet of paper draw the molecule that fits the given description. From the str

krok68 [10]

Answer:

a. 4—ethyl—5—methyloctane

b. 2,2,6—trimethyloctane

Explanation:Please see attachment for explanation

3 0

3 years ago

In order to say that carbon dioxide caused global warming scientists had to A.Come up with a mechanism that made sense and test

Bumek [7]

Answer:

Option A.

Explanation:

Option A directly tests the cause and effect. Option B simply argues it argumentatively without any solid evidence to show cause and effect. Option C only shows correlation and Option D only shows correlation as well.

6 0

3 years ago

Solution A is 0.44 M and reacts with 0.11 M of solution B. Assume that the value of x is 0, the value of y is 1, and r is 1.07 ×

xz_007 [3.2K]

Answer:

K, the rate constant = 9.73 × 10^(-1)/s

Explanation:

r = K × [A]^x × [B]^y

r = Rate = 1.07 × 10^(-1)/s

K = Rate constant

A and B = Concentration in mol/dm^-3

A = 0.44M

B = 0.11M

x = Order of reaction with respect to A = 0

y = Order of reaction with respect to B = 1

Solving, we get

r/([A]^x × [B]^y) = K

K = 1.07 × 10^(-1)/s/(0.44^0 × 0.11^1)= 0.9727

K = 0.9727

7 0

3 years ago

If a 1.00 mL sample of the reaction mixture for the equilibrium constant experiment required 32.40 mL of 0.258 M NaOH to titrate

andrey2020 [161]

Answer:

The concentration of acetic acid is 8.36 M

Explanation:

Step 1: Data given

Volume of acetic acid = 1.00 mL = 0.001 L

Volume of NaOH = 32.40 mL = 0.03240 L

Molarity of NaOH = 0.258 M

Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

Step 3: Calculate the concentration of the acetic acid

b*Ca*Va = a*Cb*Vb

⇒with b = the coefficient of NaOH = 1

⇒with Ca = the concentration of CH3COOH = TO BE DETERMINED

⇒with Va = the volume of CH3COOH = 1.00 mL = 0.001L

⇒with a = the coefficient of CH3COOH = 1

⇒with Cb = the concentration of NaOH = 0.258 M

⇒with Vb = the volume of NaOH = 32.40 mL = 0.03240 L

Ca * 0.001 L = 0.258 * 0.03240

Ca = 8.36 M

The concentration of acetic acid is 8.36 M

6 0

3 years ago