*hops like a bunny* *giggling*

How do you write 9.14 X 10^-5 in standard form?

soldi70 [24.7K]

.0000914

Since it is negative you go behind the .

so you would go 5 spaces behind the point

8 0

3 years ago

Determine whether f(x) = –5x^2 – 10x + 6 has a maximum or a minimum value.

Blizzard [7]

First,

We are dealing with parabola since the equation has a form of,

$y=ax^2+bx+c$

Here the vertex of an up - down facing parabola has a form of,

$x_v=-\dfrac{b}{2a}$

The parameters we have are,

$a=-5,b=-10, c=6$

Plug them in vertex formula,

$x_v=-\dfrac{-10}{2(-5)}=-1$

Plug in the $x_v$ into the equation,

$y_v=-5(-1)^2-10(-1)+6=11$

We now got a point parabola vertex with coordinates,

$(x_v, y_v)\Longrightarrow(-1,11)$

From here we emerge two rules:

If $a$ then vertex is max value
If $a>0$ then vertex is min value

So our vertex is minimum value since,

$a=-5\Longleftrightarrow a$

Hope this helps.

r3t40

7 0

3 years ago

A company is bidding on two projects, A and B. The probability that the company wins project A is 0.40 and the probability that

kondaur [170]

Answer:

Probability that the company wins project A or project B is 0.50.

Step-by-step explanation:

We are given that a company is bidding on two projects, A and B. The probability that the company wins project A is 0.40 and the probability that the company wins project B is 0.25.

Also, Winning project A and winning project B are independent events.

Let the Probability of winning project A = P(A) = 0.40

Probability of winning project B = P(B) = 0.25

Now, as we know that ;

Probability that the company wins project A or project B = $P(A \bigcup B)$

$P(A \bigcup B) = P(A) + P(B) - P(A \bigcap B)$

So, we have to find the value of Probability of winning project A and B, i.e;

$P(A \bigcap B)$

Since, we are given that Winning project A and winning project B are independent events which means when this condition is given then;

$P(A \bigcap B) = P(A) \times P(B)$

= 0.40 $\times$ 0.25 = 0.10

Now, Probability that the company wins project A or project B is given by;

$P(A \bigcup B) = P(A) + P(B) - P(A \bigcap B)$

= 0.40 + 0.25 - 0.10

= 0.65 - 0.10 = 0.55

Hence, probability that the company wins project A or project B is 0.50.

3 0

2 years ago

Solve x3 = 1 over 8. 1 over 2 ±1 over 2 1 over 4 ±1 over 4

cricket20 [7]

X³ = 1/8

Take the cube root of both sides.

∛x³ = ∛(1/8)

Since x³ has 3 of such x multiplying each other so we bring out 1 of the x from the cube root sign as discussed.

x = ∛((1/2)*(1/2)*(1/2))

We bring out 1 of the (1/2) out of the cube root sign as well.

x = 1/2

So the answer is the first option. 1 over 2.

I hope this helps.

7 0

3 years ago

Trigonometry Find x 8.3 34 degrees

Diano4ka-milaya [45]

Answer:

Step-by-step explanation:

In Triangle

A

B

C

with the right angle at

C

, let

a

,

b

, and

c

be the opposite, the adjacent, and the hypotenuse of

∠

A

. Then, we have

sin

A

=

a

c

⇒

m

∠

A

=

sin

−

1

(

a

c

)

sin

B

=

b

c

⇒

m

∠

B

=

sin

−

1

(

b

c

)

I hope that this was helpful.

Wataru · 1 · Oct 29 2014

How do you find all the missing angles, if you know one of the acute angles of a right triangle?

The sum of the measures of all the angles in a triangle is always equal to

180

o

.

In a right triangle, however, one of the angles is already known: the right angle, or the

90

o

angle.

Let the other two angles be

x

and

y

(which will be acute).

Applying these conditions, we can say that,

x

+

y

+

90

o

=

180

o

x

+

y

=

180

o

−

90

o

x

+

y

=

90

o

That is, the sum of the two acute angles in a right triangle is equal to

90

o

.

If we know one of these angles, we can easily substitute that value and find the missing one.

For example, if one of the angles in a right triangle is

25

o

, the other acute angle is given by:

25

o

+

y

=

90

o

y

=

90

o

−

25

o

y

=

65

o

Tanish J. · 1 · Nov 26 2014

How do you know what trigonometric function to use to solve right triangles?

Right triangles are a special case of triangles. You always know at least one angle, the right angle, and depending on what else you know, you can solve the rest of the triangle with fairly simple formulas.

http://etc.usf.edu/clipart/36500/36521/tri11_36521.htm

If you know any one side and one angle, or any two sides, you can use the pneumonic soh-cah-toa to remember which trig function to use to solve for others.

s

−

i

n

(

θ

)

=

o

−

pposite

/

h

−

ypotenuse

c

−

o

s

(

θ

)

=

a

−

djacent

/

h

−

ypotenuse

t

−

a

n

(

θ

)

=

o

−

pposite

/

a

−

djacent

Opposite refers to the side which is not part of the angle, adjacent refers to the side that is part of the angle, and the hypotenuse is the side opposite the right angle, which is

C

in the image above.

For example,lets say you know the length of

a

and the value of angle

A

in the above triangle. Using the cosine function you can solve for

c

, the hypotenuse.

cos

(

A

)

=

a

c

Which rearranges to;

c

=

a

cos

(

A

)

If you know the length of both sides

a

and

b

, you can solve for the tangent of either angle

A

or

B

.

tan

(

A

)

=

a

b

Then you take the inverse tangent,

tan

−

1

to find the value of

A

.

Zack M. · 4 · Dec 7 2014

What are inverse trigonometric functions and when do you use it?

Inverse trigonometric functions are useful in finding angles.

Example

If

cos

θ

=

1

√

2

, then find the angle

θ

.

By taking the inverse cosine of both sides of the equation,

⇒

cos

−

1

(

cos

θ

)

=

cos

−

1

(

1

√

2

)

since cosine and its inverse cancel out each other,

⇒

θ

=

cos

−

1

(

1

√

2

)

=

π

4

I hope that this was helpful.

Wataru · 1 · Nov 2 2014

What is Solving Right Triangles?

Solving a right triangle means finding missing measures of sides and angles from given measures of sides and angles.

I hope that this was helpful.

Wataru · 3 · Nov 6 2014

5 0

2 years ago