Answer:
He must work additional 8 hours.
Step-by-step explanation:
Because 1550.00/20=7.75
217.00/7.75=28
28-20=8
So,an additional of 8 hours
Answer:
3/12
Step-by-step explanation:
to rename the fraction with the common denominator of 12, u have to multiply 1/4 by 3/3 to get 3/12. You can check ur answer by simplifying your answer. 3/12=1/4
Answer:
arc RS = 116°
Step-by-step explanation:
Since the 2 chords are congruent then their minor arcs are congruent, that is
SR = TU, substitute values
6x - 28 = 4x + 20 ( subtract 4x from both sides )
2x - 28 = 20 ( add 28 to both sides )
2x = 48 ( divide both sides by 2 )
x = 24
Then
arc RS = 6x - 28 = 6(24) - 28 = 144 - 28 = 116°
The maximum height of the rocket is 43.89 feet
<h3>How to write the function</h3>
The general function is given as:
h(t) = -16t^2 + vt + h
The initial velocity is
v = 53
So, we have:
h(t) = -16t^2 + 53t + h
The initial height is
h = 0
So, we have:
h(t) = -16t^2 + 53t
Hence, the function of the height is h(t) = -16t^2 + 53t
<h3>The maximum height of the rocket</h3>
In (a), we have:
h(t) = -16t^2 + 53t
Differentiate the function
h'(t) = -32t + 53
Set to 0
-32t + 53 = 0
This gives
-32t = -53
Divide by -32
t = 1.65625
Substitute t = 1.65625 in h(t) = -16t^2 + 53t
h(1.65625) = -16 * 1.65625^2 + 53 * 1.65625
Evaluate
h(1.65625) = 43.890625
Approximate
h(1.65625) = 43.89
Hence, the maximum height of the rocket is 43.89 feet
<h3>Time to hit the ground</h3>
In (a), we have
h(t) = -16t^2 + 53t
Set to 0
-16t^2 + 53t = 0
Divide through by -t
16t - 53 = 0
Add 53 to both sides
16t = 53
Divide by 16
t = 3.3125
Hence, the time to hit the ground is 3.3125 seconds
<h3>The graph of the function h(t)</h3>
See attachment for the graph of the function h(t)
Read more about height functions at:
brainly.com/question/12446886
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