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3 years ago

Write the change of the following particles?

Chemistry

1 answer:

dmitriy555 [2]3 years ago

5 0

Explanation:

neutron- neutral

proton- positive (+)

electron- negative (-)

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How many oxygen molecules are produced when 3.2×1022 molecules of water decompose?

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3 years ago

Give 2 examples of how plants and animals affect their environment

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4 years ago

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A) What volume of butane (C 4 H 10 ) can be produced at STP, from the reaction of 13.45 g of carbon with 17.65 L of hydrogen gas

UNO [17]

From the stoichiometry of the reaction, carbon is in excess and 5.856 g s left over.

<h3>What is the volume of butane produced?</h3>

The reaction can be written as; 4C(s) + 5H2(g) -----> C4H10(g)

Number of moles of C = 13.45 g/1 2g/mol = 1.12 moles

If 1 mole of hydrogen occupies 22.4 L

x moles of hydrogen occupies 17.65 L

x = 0.79 moles

Now;

4 moles of carbon reacts with 5 moles of hydrogen

1.12 moles of carbon reacts with 1.12 moles * 5 moles/4 moles

= 1.4 moles of hydrogen

Hence hydrogen is the limiting reactant here and carbon is in excess.

If 4 moles of carbon reacts with 5 moles of hydrogen

x moles of carbon reacts with 0.79 moles of hydrogen

x = 0.632 moles

Number of moles of carbon unreacted = 1.12 moles - 0.632 moles

= 0.488 moles

Mass of carbon unreacted = 0.488 moles * 12 g/mol

= 5.856 g

Volume of butane produced is obtained from;

5 moles of hydrogen produces 1 mole of butane

0.79 moles of hydrogen produces 0.79 moles * 1 mole/ 5 moles

= 0.158 moles

1 mole of butane occupies 22.4 L

0.158 moles of butane occupies 0.158 moles * 22.4 L/ 1 mole

= 3.53 L

Learn more about stoichiometry:brainly.com/question/9743981

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2 years ago

3 Mg + 1 Fe2O3 --> 2 Fe + 3 MgO

Gala2k [10]

Answer:

Fe₂O₃ is the limiting reactant.

7.57 g of MgO are formed.

Explanation:

3 Mg + 1 Fe₂O₃ → 2 Fe + 3 MgO

First we convert the given masses of both reactants into moles, using their respective molar masses:

15.6 g Mg ÷ 24.305 g/mol = 0.642 mol Mg

10.0 g Fe₂O₃ ÷ 159.69 g/mol = 0.0626 mol Fe₂O₃

0.0626 moles of Fe₂O₃ would react completely with (3 * 0.0626 ) 0.188 moles of Mg. As there are more Mg moles than required, Mg is the reactant in excess; thus, Fe₂O₃ is the limiting reactant.

We now calculate how many MgO moles are produced, using the number of moles of the limiting reactant:

0.0626 mol Fe₂O₃ * $\frac{3molMgO}{1molFe_2O_3}$ = 0.188 mol MgO

Finally we convert moles of MgO into grams:

0.188 mol MgO * 40.3 g/mol = 7.57 g

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3 years ago

Count the number of each type of atom in the equation below, and then balance the equation. Write In the numbers of atoms and co

Studentka2010 [4]

Answer:

Balanced equation

CS2(l) + 3O2(g)------> CO2(g) + 2SO2(g)

Explanation:

For a chemical equation to be balanced, the number of atoms of each element on the left Hans side of the reaction equation must equal the number of atoms of that element on the right hand side of the reaction equation.

Atoms of oxygen are six on both sides of the reaction equation. Atoms of sulphur are two while there is only one atom of carbon on both sides of the reaction equation.

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3 years ago

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