The given question is incomplete. The complete question is as follows.
The enthalpy of formation of ozone is 142.7 kJ / mol. The bond energy of 
is 498 kJ / mol. What is the average O=O bond energy of the bent ozone molecule O=O=O?
Explanation:
The given reaction is as follows.
The value of 
for 2 moles of ozone is 
= 285.4 kJ/mol.
So, in this reaction three O=O bonds are broken down and four O-O bonds of ozone are formed.
Expression for the enthalpy of reaction is as follows.
285.4 kJ/mol = 
285.4 kJ/mol = 
-1208.6 kJ/mol = 
= 604.3 kJ/mol
Now, the average bond enthalpy of O-O bond in is as follows.
= 
kJ/mol
= 201.43 kJ/mol
Thus, we can conclude that for the given reaction average bond enthalpy of an oxygen-oxygen bond in is 201.43 kJ/mol.
Answer:
75%
Explanation:
RR , Rr , Rr all result in dominant trait
The main <span>hazard </span>is the Radiation and the Gamma rays that are dispersed
Explanation:
This is feasible single displacement chemical reaction. In this reaction, Zinc displaces cadmium from the chlorate solution:
Zn + Cd(ClO₃)₂ → Zn(ClO₃)₂ + Cd
A single displacement reaction is a reaction in which one specie replaces another.
The main driving force in this kind of reaction is the position of the displacing species in the activity series.
In the series, metals that are higher up are more reactive and they will displace the lower ones from solution.
Cadmium is lower in the series and Zn is higher up.
Zn is more reactive than Cd and will displace it form the solution and it gives the expression:
Zn + Cd(ClO₃)₂ → Zn(ClO₃)₂ + Cd
learn more:
Chemical reactions brainly.com/question/3953793
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