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2 years ago

9. Factor 12-15x (show work here)

Mathematics

2 answers:

Ann [662]2 years ago

8 0

Answer:

mean

Step-by-step explanation:

mean ka hai iska i don't know

Alchen [17]2 years ago

6 0

Answer:

Factor 3 out of 12.

3(4)−15x

Factor 3 out of −15x.

3(4)+3(−5x)

Factor 3 out of 3(4)+3(−5x).

3(4−5x)

Step-by-step explanation:

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Determine the equation of the circle graphed below.

myrzilka [38]

Answer:

$= > {x}^{2} + {y}^{2} + 6x - 14y + 49 = 0$

Step-by-step explanation:

From the graph we can see that

Diameter = 6 units

=> Radius = 3 units and centre is at (-3,7)

=> Equation is Circle with centre (-3,7) and radius of 3 units will be

$= > {(x + 3)}^{2} + {(y - 7)}^{2} = {3}^{2}$

$= > ( {x}^{2} + 6x + 9) + ( {y}^{2} - 14y + 49) = 9$

$= > {x}^{2} + {y}^{2} + 6x - 14y + 49 = 0$

4 0

2 years ago

tasha has 24 new pieces of art. 1/6 are photo's and 2/3 are paintings. how many more paintings are there than photos?

ella [17]

0.5 x 24 = 12
The answer is 12

3 0

2 years ago

Tristen is building 3 trophies using Legos. He needs 324 total Legos. Tristen uses 220 Legos for the largest trophy and 135 Lego

Alexeev081 [22]

Answer: 166

Step-by-step explanation:

Number of trophies = 3

Total Legos required for all trophies = 324

Number of Legos for largest trophy(A) = 220

Number of Legos for smallest trophy(B) = 135

Number of Legos required for final trophy(C)

Total Legos = [Number of Legos for largest trophy(A) + Number of Legos for smallest trophy(B) + Number of Legos required for final trophy(C)]

324 = 220 +135 + C

324 = 355 + C

324 - 355 = C

-31 = C

135 + 31 = 166

6 0

2 years ago

Read 2 more answers

The graph of the function y=f(x)+35 can be obtained from the graph of y=f(x) by one of the following actions:

SCORPION-xisa [38]

I’m pretty sure it’s the second one if not I’m so sorry

3 0

2 years ago

A colony of bacteria is growing at a rate of 0.2 times its mass. Here time is measured in hours and mass in grams. The mass of t

11Alexandr11 [23.1K]

Answer:

Question 1: $dm/dt=0.2m$

Question 2: $m=Ae^{(0.2t)}$

Question 3: $m=10e^{(0.2t)}$

Question 4: $m=10g$

Explanation:

Question 1: Write down the differential equation the mass of the bacteria, m, satisfies: m′= .2m

a) By definition: $m'=dm/dt$

b) Given: $rate=0.2m$

c) By substitution: $dm/dt=0.2m$

Question 2: Find the general solution of this equation. Use A as a constant of integration.

a) Separate variables

$dm/m=0.2dt$

b) Integrate

$\int dm/m=\int 0.2dt$

$ln(m)=0.2t+C$

c) Antilogarithm

$m=e^{0.2t+C}$

$m=e^{0.2t}\cdot e^C$

$e^C=A\\\\m=Ae^{(0.2t)}$

Question 3. Which particular solution matches the additional information?

Use the measured rate of 4 grams per hour after 3 hours

$t=3hours,dm/dt=4g/h$

First, find the mass at t = 3 hours

$dm/dt=0.2m\\\\4=0.2m\\\\m=4/0.2\\\\m=20g$

Now substitute in the general solution of the differential equation, to find A:

$m=Ae^{(0.2t)}\\\\20=Ae^{(0.2\times 3)}\\\\A=20/e^{(0.6)}\\\\A=10.976$

Round A to 1 significant figure:

A = 10.

Particular solution:

$m=10e^{(0.2t)}$

Question 4. What was the mass of the bacteria at time =0?

Substitute t = 0 in the equation of the particular solution:

$m=10e^{0}\\\\m=10g$

3 0

2 years ago