Given:
A(3,0)
B(1,-2)
C(3,-5)
D(7,-1)
1) reflect across x=-4
essentially calculate the difference between the x=-4 line and Px and "add" it in the other direction to x=-4
A(-4-(3-(-4)),0)=A(-11,0)
B(-4-(1-(-4)),-2)=B(-9,-2)
C(-4-(3-(-4),-5))=C(11,-5)
D(-4-(7-(-4)),-1)=D(-15,-1)
2) translate (x,y)->(x-6,y+8)
A(-3,8)
B(-5,6)
C(-3,3)
D(1,7)
3) clockwise 90° rotation around (0,0), flip the x&y coordinates and then decide the signs they should have based on the quadrant they should be in
A(0,-3)
B(-2,-1)
C(-5,-3)
D(-1,-7)
D) Dilation at (0,0) with scale 2/3, essentially multiply all coordinates with the scale, the simple case of dilation, because the center point is at the origin (0,0)
A((2/3)*3,(2/3)*0)=A(2,0)
B((2/3)*1,(2/3)*-2)=B(2/3,-4/3)
C((2/3)*3,(2/3)*-5)=C(2,-10/3)
D((2/3)*7,(2/3)*-1)=D(14/3,-2/3)
Answer:
(1)
type-A:
type-B:
(2)
Step-by-step explanation:
We are given
type-A:
type-B:
(1)
At initial means t=0
For type-A:
we can plug t=0
For type-B:
we can plug t=0
(2)
we can set f(t)=g(t)
and then we can solve for t
we can draw graph of f(t) and g(t)
and then we can find intersection point
so, we got
You can make an equation for each situation where x is the number of bags and y is equal to the total number of oranges.
5x + 1 = y
4x + 3 = y
With substitution: 5x + 1 = 4x + 3
Solve for x.
5x - 2 = 4x
x - 2 = 0
x = 2
There is 2 bags, so plug that into either equation:
4x + 3 = y
y = 4*2 + 3
y = 11 oranges
-8/2. eight and two thirds times 30 is 260, and seven percent of 270 is 91/5, and subtracted by 10 is -8.2
