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stiv31 [10]
3 years ago
10

Write the equation y+5=-10(x-1) into standard form

Mathematics
1 answer:
olga55 [171]3 years ago
8 0

Answer:

10x + y = 5

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties

<u>Algebra I</u>

Point-Slope Form: y - y₁ = m(x - x₁)  

  • x₁ - x coordinate
  • y₁ - y coordinate
  • m - slope

Standard Form: Ax + By = C

Step-by-step explanation:

<u>Step 1: Define</u>

Point-Slope Form:   y + 5 = -10(x - 1)

<u>Step 2: Find Standard Form</u>

  1. Distribute -10:                              y + 5 = -10x + 10
  2. Add 10x on both sides:               10x + y + 5 = 10
  3. Subtract 5 on both sides:           10x + y = 5

And we have our final answer!

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If x = 2, y = 3 and z = 5, calculate the following: 5x - z
nikdorinn [45]
5*2 - 5
5*2=10
10-5=5
5 0
3 years ago
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 139 millimeters,
FinnZ [79.3K]

Answer:

0.4010 = 40.10% probability that the sample mean would differ from the population mean by more than 0.8 millimeters

Step-by-step explanation:

To solve this question, we need to understan the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 139, \sigma = 6, n = 40, s = \frac{6}{\sqrt{40}} = 0.9487

Either the sample mean differs by 0.8 mm or less from the population mean, or it differs by more. The sum of these probabilities is decimal 1.

Probability it differs by less than 0.8mm

pvalue of Z when X = 139 + 0.8 = 139.8mm subtracted by the pvalue of Z when X = 139 - 0.8 = 138.2 mm

X = 139.8

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{139.8 - 139}{0.9487}

Z = 0.84

Z = 0.84 has a pvalue of 0.7995

X = 138.2

Z = \frac{X - \mu}{s}

Z = \frac{138.2 - 139}{0.9487}

Z = -0.84

Z = -0.84 has a pvalue of 0.2005

0.7995 - 0.2005 = 0.5990

What is the probability that the sample mean would differ from the population mean by more than 0.8 millimeters?

p + 0.5990 = 0.4010

0.4010 = 40.10% probability that the sample mean would differ from the population mean by more than 0.8 millimeters

7 0
3 years ago
In the first half of a basketball game, a player scored 9 points on free throws and then scored a number of 2-port
Mashcka [7]

Answer: I thin The first one 2r+3r+9

Step-by-step explanation: Because he scored a number of 2 port shots which means he scored more than one but the 9 points is just 9 points from free throws which gives only 1 point each and 3 port shots and much as 2 point shots so 3r also

2r+3r+ just 9

8 0
2 years ago
Hi can someone help me with question and how you got the answer? thanks :)
Triss [41]

Answer:

Convert 27 4/3 to an improper fraction.

Step-by-step explanation:

Exact Form:

85/3

Decimal Form:

28.¯3

Mixed Number Form:

28 1/3

5 0
3 years ago
Read 2 more answers
Please I need step by step solution.​
4vir4ik [10]

Answer:

  A)  2C

Step-by-step explanation:

The relevant rule of logarithms is ...

  log(x²) = 2·log(x)

__

We know that 64 = 8². So, ...

  log(64) = log(8²) = 2·log(8)

We are given that log(8) = C, so 2·log(8) = 2C

__

Here, all logarithms are to the base 9. That does not change the relations shown.

7 0
2 years ago
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