In a galvanic cell, the flow of electrons will be from the anode to cathode through the circuit .
Whether a cell is an electrolysis cell (non-spontaneous chemistry driven by forcing electricity from an external energy source) or a galvanic cell (spontaneous chemistry driving electricity), will determine the charge of the anode and the cathode. Depending on where the electrons encounter resistance and find it difficult to pass, a negative charge may emerge. Therefore, you cannot determine the direction of the current just on the charge on the electrode.
Oxidation and reduction always take place at the anode and cathode, respectively.
An element undergoes oxidation when it surrenders one or more electrons to become more positively charged. These electrons leave the chemicals in any type of cell and travel to the anode, where they enter the external circuit.
An element picks up an electron during reduction to become more negatively charged (less positive, lower oxidation state). These electrons are captured from the external circuit at the cathode in both types of cells.
Therefore, no matter what kind of cell you are dealing with, the oxidizing chemicals at the anode transfer the electrons to the external circuit; these electrons then move through the circuit from the anode to the cathode, where they are captured by the reducing chemicals. The electrons always go from the anode to the cathode via the external circuit.
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Answer:
The pressure is 1, 22 atm.
Explanation:
We use deal gas formula. First, we convert the unit of temperature in Celsius into Kelvin. We use the constant R= 0,082 l atm /K mol.Then, we solve P (pressure).
0°C=273 K 25°C= 273 + 25= 298 K
PV=nRT -----> P= (nRT)/V
P= (0,5 mol x 0,082 l atm /K mol x 298 K)/ 10 L
<em>P= 1, 2218 atm</em>
Answer:
it answer D because waste is flowing thru the air
<span>In chemistry, a catalyst can speed up the reaction (or make it initiate easier) by altering the activation energy, lowering it enough to allow the reactants to react more easily. Some negative catalysts or inhibitors can do the same by increasing the activation energy.
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