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bazaltina [42]
2 years ago
10

What is the 3-dimensional orientation of a sublevel known as?

Chemistry
1 answer:
RoseWind [281]2 years ago
3 0

The 3-dimensional orientation of a sublevel is known as atomic orbital.

In quantum mechanics, Atomic orbitals are locations around an atom's nucleus where electrons are most likely to be at any particular time(specific orbits). These specific orbits exist in levels and can be broken down into sublevels.

Each sublevel has an orbital and it is oriented differently in 3-dimensional space.

The atomic orbital is a mathematical function that depicts how one or two electrons in an atom behave as seen in waves.

Learn more about atomic orbitals here:

brainly.com/question/1832385

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Answer:

Time allowed for incubation, size of the dish, the amount of light, amount of agar, the type of agar…etc

Explanation:

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Identify the Lewis acid and Lewis base from among the reactants in each of the following equations.
Alex

Answer:

Part A

Ag+ is the Lewis acid and NH3 is the Lewis base.

Part B

AlBr3 is the Lewis acid and NH3 is the Lewis base.

Part C

AlCl3 is the Lewis acid and Cl− is the Lewis base.

Explanation:

A Lewis acid is any specie that accepts a lone pair of electrons. Ag^+, AlBr3 and AlCl3 all accepted lone pairs of electrons according to the three chemical reaction equations shown. Hence, they are Lewis acids.

A Lewis base donates a lone pair of electrons. They include neutral molecules having lone pair of electrons such as NH3 or negative ions such as Cl- .

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1. What is a taste bud?
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A 2.00 L sample of gas at 35C is to be heated at constant pressure until it reaches a volume of 5.25 L. To what Kelvin temperatu
Anastaziya [24]

Answer:

The sample will be heated to 808.5 Kelvin

Explanation:

Step 1: Data given

Volume before heating = 2.00L

Temperature before heating = 35.0°C = 308 K

Volume after heating = 5.25 L

Pressure is constant

Step 2: Calculate temperature

V1 / T1 = V2 /T2

⇒ V1 = the initial volume = 2.00 L

⇒ T1 = the initial temperature = 308 K

⇒ V2 = the final volume = 5.25 L

⇒ T2 = The final temperature = TO BE DETERMINED

2.00L / 308.0 = 5.25L / T2

T2 = 5.25/(2.00/308.0)

T2 = 808.5 K

The sample will be heated to 808.5 Kelvin

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when particles of matter are in direct contact and movement occurs in the substance due to convection, thermal energy transfers
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Thermal energy transfers in a solid state, due to convection, in metalic substances.

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