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ella [17]
3 years ago
15

3. Categorize each statement as true or false. At the critical angle, no light is reflected and all light is transmitted.During

refraction, the ray that travels through the second medium is called the incident ray.The angle of refraction is measured from the perpendicular to the boundary between two materials.The speed of light in a medium is always less than the speed of light in a vacuum.The virtual image of a pencil in a glass of water is closer to the viewer than the actual pencil. True False
Physics
1 answer:
melamori03 [73]3 years ago
7 0

Answer:

A) False

B) False

C) True

D) True

E) True

Explanation:

A) At the critical angle, no light is reflected and all light is transmitted: This statement is false because critical angle has nothing to do with whether all light is transmitted.

B) During refraction, the ray that travels through the second medium is called the incident ray: Statement is False because the ray in the second medium is called refracted ray.

C) The angle of refraction is measured from the perpendicular to the boundary between two materials: Statement is true.

D) The speed of light in a medium is always less than the speed of light in a vacuum: Statement is true because speed of light in vacuum is approximately 300,000 km/s and no other light can go higher than that.

E) The virtual image of a pencil in a glass of water is closer to the viewer than the actual pencil: Statement is true.

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A charged particle having mass 6.64 x 10-27 kg (that of a helium atom) moving at 8.70 x 105 m/s perpendicular to a 1.30-T magnet
Fiesta28 [93]

Answer:

the charge of the particle is 2.47 x 10⁻¹⁹ C

Explanation:

Given;

mass of the particle, m = 6.64 x 10⁻²⁷ kg

velocity of the particle, v = 8.7 x 10⁵ m/s

strength of the magnetic field, B = 1.3 T

radius of the circle, r = 18 mm = 1.8 x 10⁻³ m

The magnetic force experienced by the charge is calculated as;

F = ma = qvB

where;

q is the charge of the particle

a is the acceleration of the charge in the circular path

a = \frac{v^2}{r} \\\\ma = qvB\\\\q = \frac{ma}{vB} \\\\q = \frac{mv^2}{rvB} = \frac{mv}{rB} \\\\q = \frac{(6.64\times 10^{-27} ) \times (8.7\times 10^5)}{(1.8\times 10^{-2}) \times (1.3)} \\\\q = 2.47 \ \times 10^{-19} \ C

Therefore, the charge of the particle is 2.47 x 10⁻¹⁹ C

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3 years ago
A cement truck of mass 14,000 kg moving 10m/s slams into a wall and comes to a halt in .2s. What is the force of impact on the t
skelet666 [1.2K]

And it’s x10 is 100000

6 0
3 years ago
What is the kinetic energy f a 25kg object movingat a velocity of 10m/s?
alex41 [277]
Using K.E=1/2MV^2
answer is 125joules
5 0
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What two types of atoms make a Covalent bond
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4 0
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A 5,000 kg satellite is orbiting the Earth in a circular path. The height of the satellite above the surface of the Earth is 800
Arada [10]

Explanation:

The given data is as follows.

            m = 5000 kg,            h = 800 km = 0.8 \times 10^{6} m

    R_{e} = 6.37 \times 10^{6} m,    r = R + h = 7.17 \times 10^{6} m

   M_{e} = 5.98 \times 10^{24} kg,   G = 6.67 \times 10^{-11} Nm^{2}/kg^{2}

As we know that,

              \frac{mv^{2}}{r} = \frac{GmM_{e}}{r^{2}}

                      v = \sqrt{\frac{GM_{e}}{r^{2}}}

And, it is known that formula to calculate angular velocity is as follows.

               \omega = \frac{v}{r} = \sqrt{\frac{GM_{e}}{r^{3}}}

                            v = \sqrt{\frac{GM_{e}}{r^{3}}}

                               = \sqrt{\frac{6.67 \times 10^{-11} Nm^{2}/kg^{2} \times 5.98 \times 10^{-24} kg^{-2}}{(7.17 \times 10^{6} m)^{3}}}

                                = 1.0402 \times 10^{-3} rad/s

Thus, we can conclude that speed of the satellite is 1.0402 \times 10^{-3} rad/s.

6 0
3 years ago
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