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vlada-n [284]
2 years ago
10

The mass after a physical change, such as ice melting into water, stays the same a. -true b. -false.

Physics
1 answer:
kupik [55]2 years ago
3 0

Answer:

Yes, it can be destroyed.The total amount of matter (atoms) before and after a chemical reaction (change), remains the same.

Explanation:

hope this helps

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Which of the following simple machines is not properly identified? A. Scissors: lever B. Pizza cutter: wedge C. Screw: wheel and
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Pretty sure the answer is   C. Screw: wheel and axle

8 0
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A rock falls from the top of a hill to the bottom. The total energy of the rock at the top isn’t the same as the sum of its pote
mart [117]

Answer:

A) some of the rocks energy is transformed to thermal energy

Explanation:

If we neglect air resistance during the fall of the rock, than the mechanical energy of the rock (which is sum of its potential energy and its kinetic energy) would be constant during the entire motion, so the total energy of the rock at the top would be the same as the sum of its potential energy and kinetic energy at the bottom.

However, this not occurs, due to the presence of air resistance. In fact, air resistance acts against the fall of the rock, and because of the friction between the molecules of air and the surface of the rock, the rock loses part of its energy. This energy is converted into thermal energy of the molecules of the air.

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Which of these is a type of matter that rarely interacts with other matter and is created in some nuclear fusion reactions withi
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Explanation:

7 0
3 years ago
What affect does distance have on the force of gravity
DaniilM [7]

Answer:

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Explanation:

3 0
3 years ago
A 50-kg toboggan is coasting on level snow. As it passes beneath a bridge, a 20-kg parcel is dropped straight down and lands in
timama [110]

Answer:

KE2/KE1=0.71

Explanation:

By conservation of the linear momentum:

m1*V1 = (m1+m2)*V2

Solving for V2:

V2 = \frac{m1}{m1+m2}*V1

The kinetic energies are:

KE1=1/2*m1*V1^2

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KE2 = 1/2*(m1+m2)*(\frac{m1}{m1+m2}*V1)^2

Simplifying:

KE2 = 1/2*\frac{m1^2}{m1+m2}*V1^2

The ratio will be:

KE2/KE1=\frac{1/2*\frac{m1^2}{m1+m2}*V1^2}{1/2*m1*V1^2} =\frac{m1}{m1+m2}

KE2/KE1=0.71

5 0
3 years ago
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