Answer:
v (speed) = S / t = 4 * 400 m / (6 * 60 sec) = 4.4 m/s
The average velocity is zero because there is no net vector displacement.
Answer:
<h3>
2.3125m/s²</h3>
Explanation:
Using the equation of motion v² = u²+2aS
v is the final velocity = 120km/hr
120km/hr = 120 * 1000/1 * 3600 = 33.3m/s
u is the initial velocity = 0m/s
a is the acceleration
S is the distance covered = 240m
On substituting the given parameters
33.3² = 0²+2a(240)
33.3² = 480a
1110 = 480a
a = 1110/480
a = 2.3125m/s²
Hence the minimum constant acceleration that the aircraft require to be airborne after a takeoff run of 240 m is 2.3125m/s²
The tension, T, in each rope is T= mg/2Sinθ
<h3>What is tension force?</h3>
Tension refers to the pulling force in a string which acts in an opposite direction to the force pulling on it.
The tension in each of the ropes are equal since they both make the same angle with the vertical.
Assume the angle the ropes make with the vertical are both θ.
Let the tension in each be T₁ and T₂
Also, T₁ = T₂ = T
T₁Sinθ + T₂Sinθ = mg
2TSinθ = mg
T = mg/2Sinθ
Therefore, the tension, T, in each rope is T = mg/2Sinθ
Learn more about tension at: brainly.com/question/14336853
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