I believe it’s 2020m? I’m sorry if it’s wrong
Answer:
decreases
Explanation:
The angular frequency of the mass is given by

where, k is the spring constant and m be the mass of the body which is doing oscillations.
if the mass of the body increases, so the value of angular frequency decreases, as the angular frequency is inversely proportional to the square root of the mass of the body.
Answer:
0.001225 kg/L × 720 000 000 L = 882000 kg
Explanation:
Given:
The equation to solve is given as:
0.001225 kg/L × 720 000 000 L = ?
Let us write each term of the product in terms of power of 10.
As 0.001225 has 6 digits after the decimal place, therefore, we use the exponent 6 for 10 and the sign is negative. This gives,

Now, for 720000000 L there are 6 zeros after 720. So, we use exponent 6 but with a positive sign. This gives,

Now, finding the product, we get:

Therefore, the product is equal to:
0.001225 kg/L × 720 000 000 L = 882000 kg
Gravity affet everything and it touches nothing.
Hope this helps!
Answer:
a)the possible frequencies are 521hz ,522hz, 523, 524hz,525hz
b) 526hz
c)0.989 or a 1.14% decrease in tension
Explanation:
a) While tuning a string at 523 Hz,piano tuner hears 2.00 beats/s between a reference oscillator and the string.
The possible frequencies of the string can be calculated by
fl=f' - B
where
fl= lower limit of the possible frequency
f'= frequency of the string
B= beat heard by the tuner
fl= 523hz + Or - (2beats/secs * 1hz/1beat per sc)
fl= 521hz or 525hz
So the possible frequencies are 521hz ,522hz, 523, 524hz,525hz
b)fl=f' - B
523hz= f' - 3
f'= 523 + 3= 526hz
c) The tension is directly proportional to the square of the frequencies
T1/T2 =f1^2/f2^2
523^2 / 526^2 = 0.989 or a 1.14% decrease in tensio