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1 year ago

the focal length of a simple magnifier is 8.50 cmcm . assume the magnifier to be a thin lens placed very close to the eye.

Physics

1 answer:

Igoryamba1 year ago

5 0

When the object is at the focal point the angular magnification is 2.94.

Angular magnification:

The ratio of the angle subtended at the eye by the image formed by an optical instrument to that subtended at the eye by the object when not viewed through the instrument.

Here we have to find the angular magnification when the object is at the focal point.

Focal length = 6.00 cm

Formula to calculate angular magnification:

Angular magnification = 25/f

= 25/ 8.5

= 2.94

Therefore the angular magnification of this thin lens is 2.94

To know more about angular magnification refer:: brainly.com/question/28325488

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Answer:

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We know the object has a mass of 50 kilograms. We also know it is a traveling at a rate of 60 m/s. Velocity is the speed of something, so the velocity of the object is 60 m/s.

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Substitute these values into the formula.

$KE=\frac{1}{2}*50*60^2$

First, evaluate the exponent: 60^2. 60^2 is the same as multiplying 60, 2 times.

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Multiply 1/2 and 3,600, or divide 3,600 by 2.

$KE=90,000$

Add appropriate units. Kinetic energy uses Joules, or J.

$KE=90,000 Joules$

The kinetic energy of the object is 90,000 Joules

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Dos cargas puntuales están fijas en el eje x: q1 = 6.0µC está en el origen, O, con x1 = 0.0 cm, y q2 = –3.0 µC está situada en e

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