Answer:
t_pass = 2.34 m
t_stop = 4.68 s
Thus, for the car passing at constant speed the pedestrian will have to wait less.
Explanation:
If the car is moving with constant speed, then the time taken by it will be given as:
where,
t_pass = time taken = ?
D = Distance covered = 23 m
v = constant speed = (22 mi/h)(1609.34 m/1 mi)(1 h/3600 s) = 9.84 m/s
Therefore,
<u>t_pass = 2.34 m</u>
<u></u>
Now, for the time to stop the car, we will use third equation of motion to get the acceleration first:
Now, for the passing time we use first equation of motion:
<u>t_stop = 4.68 s</u>
Answer:
The estimated time of arrival at the destination Airport will be 1730 PST.
Explanation:
Given:
Time at which flight departs from airport = 1615 MST
Duration of flight the reach destination airport = 2 hour 15 minute.
We need to find the estimated time of arrival at the destination airport.
Solution:
Now Given:
The Destination Airport is located in Pacific standard time zone.
Now first we will find the Arrival of flight at destination airport in MST.
Now we can say that;
Arrival of flight at destination airport will be equal to sum of Time at which flight departs from airport and Duration of flight the reach destination airport.
Arrival of flight at destination airport in MST =
Now We know that;
Mountain standard time is 1 hour ahead then Pacific Standard time.
Now Arrival of flight at destination airport in MST = 1830 MST
Arrival of flight at destination airport in PST = 1730 PST.
Hence The estimated time of arrival at the destination Airport will be 1730 PST.
Answer:
Explanation:
The bulk modulus is a constant that describes how resistant a substance is to compression.
It is defined as the ratio between increase in pressure and the resulting decrease in a volume of the material.
It is given by a formula :
OR
where:
& are the change in volume and change in pressure respectively.
V= original volume
According to the given:
So,
.................................(1)
&
..................................(2)
From the given conditions we compare equations (1) & (2):
cancelling the equal terms
The material in first case undergoes twice the volume reduction than that of the material in first case under the given conditions.
The dimension of K is M/ T^2
according to the question T=2π square root ofm/k here 2 pi is constant so
T= root of m /k and root of k = root of m/ T now by squaring on both the sides we get the answer k= M/ T^2
complete question :
A spring is hanging down from the ceiling, and an object of mass m is attached to the free end. The object is pulled down, thereby stretching the spring, and then released. The object oscillates up and down, and the time T required for one complete up-and-down oscillation is given by the equation T=√2πm/k, where k is known as the spring constant. What must be the dimension of k for this equation to be dimensionally correct?
To learn more about dimension:
brainly.com/question/13314350
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Answer:
rate of infusion is 900 mL/hr
Explanation:
given data
Infuse I1 = 1000 mL
delivers = 15 gtt/mL
Infuse I2 = 300 mL
time t= 20 min
rate = 60 mL/hr
to find out
rate of infusion
solution
we know here we give 300 mL infuse in 20 min
so here for 20 min
rate of infusion is express as
rate of infusion = I2 / t
rate of infusion = 300 / 20
rate of infusion = 15 mL / min
rate of infusion = 15 × 60 = 900
so rate of infusion is 900 mL/hr