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3 years ago

- An impulse is equivalent to

Physics

1 answer:

Alik [6]3 years ago

5 0

Answer:

Explanation:

impulse Is the product of force and distance so it's generally formula

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A cell has an internal resistance of 0.02ohms and e.m.f of 2.0v calculate it's terminal p.d if it's delivers (a)5A ( b)50A

Aleksandr-060686 [28]

Answer:

(a) The terminal voltage of the cell is 1.9 V.

(b) The terminal voltage of the cell is 1.0 V.

Explanation:

Given:

(a)

E.M.F of the cell (E) = 2.0 V

Internal resistance of the cell (r) = 0.02 ohms

Current passing through the cell (I) = 5 A

Now, the potential difference across the terminals of the cell is given as:

$V=E-Ir$

Plug in the given values and solve for 'V'. This gives,

$V=2.0-(5\times 0.02)\\\\V=2.0-0.1=1.9\ V$

Therefore, the terminal voltage of the cell is 1.9 V.

(b)

E.M.F of the cell (E) = 2.0 V

Internal resistance of the cell (r) = 0.02 ohms

Current passing through the cell (I) = 50 A

Now, the potential difference across the terminals of the cell is given as:

$V=E-Ir$

Plug in the given values and solve for 'V'. This gives,

$V=2.0-(50\times 0.02)\\\\V=2.0-1.0=1.0\ V$

Therefore, the terminal voltage of the cell is 1.0 V.

4 0

3 years ago

Can someone help please I’ll mark brainless

morpeh [17]

Answer:

Synthesis Reaction

Explanation:

6 0

3 years ago

Read 2 more answers

Un contenedor de 1800 N está en reposo sobre un plano inclinado a 28°, el coeficiente de fricción entre el contenedor y el plano

babunello [35]

Answer:

F = 1480.77N

Explanation:

In order to calculate the required force to push the container with a constant velocity, you take into account the the sum of force on the container is equal to zero. Furthermore, you have for an incline the following sum of forces:

$F-Wsin\alpha-F_r=0\\\\F-Wsin\alpha-N\mu cos\alpha=0\\\\F-Wsin\alpha-W\mu cos\alpha=0$ (1)

F: required force = ?

W: weight of the container = 1800N

N: normal force = weigth

α: angle of the incline = 28°

g: gravitational acceleration = 9.8m/s^2

μ: coefficient of friction = 0.4

You solve the equation (1) for F and replace the values of the other parameters:

$F=W(sin\alpha+\mu cos\alpha)\\\\F=(1800N)(sin28\°+(0.4)cos28\°)=1480.77N$

The required force to push the container for the incline with a constant velocity is 1480.77N

8 0

3 years ago

An object with a mass of 2 kg has a force of 4 N acting on it. What is the acceleration of the object?

STatiana [176]

Answer: 2 m/s^2

Explain

£F=ma
net force = mass x acceleration
4N is a force acting on it
4N=(2kg) a
2kg is the mass
you divide the 2 over
and A= 2 m/s^2

8 0

3 years ago

WILL GIVE BRAINLEST!!

polet [3.4K]

I think the answer is c

7 0

4 years ago