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Georgia [21]
2 years ago
8

7. Simplify the answer to the equation. 3k + 4 + 2k +5​

Mathematics
2 answers:
denpristay [2]2 years ago
8 0
Answer: 5k+9
Add like terms
3k+2k=5k
5+4=9
therefore the answer is 5k+9
nignag [31]2 years ago
4 0

Answer:

5k + 9

Step-by-step explanation:

3k + 4 + 2k + 5 =

= 5k + 9

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Alex Ar [27]

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You can either use substation or you can use elimination on both of the problems

Step-by-step explanation:

5 0
3 years ago
Write the equation of the line in fully simplified slope-intercept form.
mart [117]

Answer:

y= -3x-6

Step-by-step explanation:

I believe this is correct

6 0
10 months ago
3y''-6y'+6y=e*x sexcx
Simora [160]
From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

3r^2-6r+6=0\iff r^2-2r+2=0

which has roots at r=1\pm i. This admits the two fundamental solutions

y_1=e^x\cos x
y_2=e^x\sin x

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

y_p=u_1y_1+u_2y_2

where

u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx
u_2=\displaystyle\frac13\int\frac{y_1e^x\sec x}{W(y_1,y_2)}\,\mathrm dx

and W(y_1,y_2) is the Wronskian of the fundamental solutions. We have

W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}

and so

u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx
u_1=\dfrac13\ln|\cos x|

u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx
u_2=\dfrac13x

Therefore the particular solution is

y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x

so that the general solution to the ODE is

y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x
7 0
3 years ago
Can you help me solve this radical equation √y-10 = y-2 the sqrt sign is only over the y-10
matrenka [14]
D:y-10\geq0 \wedge y-2\geq0\\
D:y\geq10 \wedge y\geq2\\
D:y\geq10\\\\
\sqrt{y-10}=y-2\\
y-10=(y-2)^2\\
y-10=y^2-4y+4\\
y^2-5y+14=0\\
\Delta=(-5)^2-4\cdot1\cdot14=25-56=-31\\
\Delta
7 0
3 years ago
How do I do this while I show all my work?
irina [24]

One way to determine the slope of a line is from two points on a line.

We can use the ones already indicated on the graph, (0,4) and (3,5).

The slope is change in y divided by change in x,

m= \dfrac{5 - 4}{3 - 0} = \dfrac 1 3

Answer: 1/3

5 0
3 years ago
Read 2 more answers
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