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Sonja [21]
3 years ago
7

Assume you have a balance of $1,900 on a credit card.

Mathematics
1 answer:
dimaraw [331]3 years ago
8 0

principal=$1900

rate =13.6 %

simple interest= $35

Time=?

SIMPLE INTEREST ={PRINCIPAL×RATE×TIME}/{100}

$35= {$1900 ×13.6× TIME}{100} /

$35×100=25840× TIME

TIME=\bold\frac{ 3500}{25840}

TIME=700/5168

TIME={\tt{\green{\underline{\underline{\huge{0.1354489164}}}}}} years

sorry I can't solve wrong answer

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A tv costs £800 plus VAT at 20% what is the total cost of the tv?
slamgirl [31]

hello friend ☺

Given :

TV cost = 800 £

VAT = 20 %

Amount of VAT

= 20% of 800

= 800 × 20 /100

= 160 £

So Total cost of TV

= original price + VAT

= 800 + 160

= 960 £

Thanks ❤

5 0
3 years ago
Can somebody solve this system equation using addition please?
givi [52]

-4x - 5y = 7

3x + 5y = -14

You can add these two equations together straightaway since the y-terms have opposite coefficients.

-4x - 5y = 7

3x + 5y = -14

+___________

-x - 0 = -7

-x = -7

x = 7

Substitute 7 for x into either of the original equations and solve algebraically to find y.

3x + 5y = -14

3(7) + 5y = -14

21 + 5y = -14

21 = -14 - 5y

35 = -5y

-7 = y

Finally, check work by substituting both x- and y-values into both original equations.

-4x - 5y = 7

-4(7) - 5(-7) = 7

-28 + 35 = 7

7 = 7

3x + 5y = -14

3(7) + 5(-7) = -14

21 - 35 = -14

-14 = -14

Answer:

x = 7 and y = -7; (7, -7).

7 0
3 years ago
Nat spent $28 on 8 DVDs. At this rate, how much would 5 DVDs cost? What is the unit rate?
mezya [45]
5 DVDs would cost 7.50 and the unit rate is 3.50
7 0
3 years ago
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A disadvantage of the contention approach for LANs, such as CSMA/CD, is the capacity wasted due to multiple stations attempting
sammy [17]

Answer:

The overview of the given problem is outlined in the following segment on the explanation.

Step-by-step explanation:

The proportion of slots or positions that have been missed due to numerous concurrent transmission incidents can be estimated as follows:

Checking a probability of transmitting becomes "p".

After considering two or even more attempts, we get

Slot fraction wasted,

= [1-no \ attempt \ probability-first \ attempt \ probability-second \ attempt \ probability+...]

On putting the values, we get

= 1-no \ attempt \ probability-[N\times P\times probability \ of \ attempts]

= 1-(1-P)^{N}-N[P(1-P)^{N}]

So that the above seems to be the right answer.

8 0
3 years ago
A recipe calls for cup
vlabodo [156]
She would need 3/8 cups of milk.
5 0
3 years ago
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