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Vadim26 [7]
3 years ago
5

Find the current flowing across the 20 Ω

Physics
2 answers:
Nesterboy [21]3 years ago
8 0

Answer:

the factor is the opposite side directly from my account and the gathered from are my lovez I have been a little while to get done before we go to watch it again I don't have a few weeks I don't think I will send it s the best pa sa

Arte-miy333 [17]3 years ago
8 0

0.23 A across the 20-ohm resistor

Explanation:

The 20-ohm and 35-ohm resistors are in parallel so their combined resistance is

(1/20) + (1/35) = 0.0786 ohm^-1 or 12.73 ohms

These two are in turn connected in series with the 15-ohm resistor so the total resistance of the circuit is

R = 12.73 ohm + 15 ohm

= 27.73 ohm

Hence, the total current drawn by the circuit is

I = V/R = (10 V)/(27.73 ohm)

= 0.36 A

The potential across the 15-ohm resistor is

V1 = IR = (0.36 A)(15 ohm)

= 5.4 V

Now the potential across the 20-ohm and 35-ohm resistors is

V2 = V - V1 = 10V - 5.4V

= 4.6 V

This means that the current across the 20-ohm resistor is

I = V/R = (4.6 V)/(20 ohm)

= 0.23 A

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