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3 years ago

I must also show my work, but I do not know how to do this problem

Mathematics

1 answer:

Vinvika [58]3 years ago

6 0

Answer:

x = 10

Step-by-step explanation:

We know that the sum of angles in a triangle is equal to 180 degrees;

This means that

71+50+(6x-1) = 180; now that you have an algebraic expression, you can solve for x.

71+49+6x=180

120+6x = 180

6x = 60

x = 10

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Find the missing angle. 9 5 x°

iragen [17]

Answer:

45 degrees

Step-by-step explanation:

the right angle is 90 degrees and one angle is 45 degrees and 90+45=135 and 180-135=45 so 45 degrees is the missing angle

5 0

3 years ago

If shape 1 is similar to shape Il and shape II is similar to shape III, what does that mean for shape I and shape III?

blagie [28]

Answer:

Step-by-step explanation:

They are also similar.

Both have 4 right angles. Both have 2 sets of parallel lines. Both have 4 equal sides.

But I think you are supposed to answer if figure 1 is similar to figure 2 and figure two is similar to figure 3 then by the transitive property, figure 1 is similar to figure 3.

7 0

3 years ago

HelllllllP it’s due today :/

svetlana [45]

Answer:

Rectangle

Step-by-step explanation:

Note the definition of a rectangle. All angles must be 90°, and opposite sides are parallel and congruent.

It says that Andre "drew a quadrilateral with <em>four right angles and two pairs of congruent sides</em>.", making rectangle a candidate as an answer.

4 0

3 years ago

You want to get from a point A on the straight shore of the beach to a buoy which is 54 meters out in the water from a point B o

anyanavicka [17]

Answer:

$x =\dfrac{45 \sqrt{6}}{ 2}$

Step-by-step explanation:

From the given information:

The diagrammatic interpretation of what the question is all about can be seen in the diagram attached below.

Now, let V(x) be the time needed for the runner to reach the buoy;

∴ We can say that,

$\mathtt{V(x) = \dfrac{70-x}{7}+\dfrac{\sqrt{54^2+x^2}}{5}}$

In order to estimate the point along the shore, x meters from B, the runner should stop running and start swimming if he want to reach the buoy in the least time possible, then we need to differentiate the function of V(x) and relate it to zero.

i.e

The differential of V(x) = V'(x) =0

= $\dfrac{d}{dx}\begin {bmatrix} \dfrac{70-x}{7} + \dfrac{\sqrt{54^2+x^2}}{5} \end {bmatrix}= 0$

$-\dfrac{1}{7}+ \dfrac{1}{5}\times \dfrac{x}{\sqrt{54^2+x^2}}=0$

$\dfrac{1}{5}\times \dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}$

$\dfrac{5x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}$

$\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{\dfrac{7}{5}}$

$\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{5}{7}$

squaring both sides; we get

$\dfrac{x^2}{54^2+x^2}= \dfrac{5^2}{7^2}$

$\dfrac{x^2}{54^2+x^2}= \dfrac{25}{49}$

By cross multiplying; we get

$49x^2 = 25(54^2+x^2)$

$49x^2 = 25 \times 54^2+ 25x^2$

$49x^2-25x^2 = 25 \times 54^2$

$24x^2 = 25 \times 54^2$

$x^2 = \dfrac{25 \times 54^2}{24}$

$x =\sqrt{ \dfrac{25 \times 54^2}{24}}$

$x =\dfrac{5 \times 54}{\sqrt{24}}$

$x =\dfrac{270}{\sqrt{4 \times 6}}$

$x =\dfrac{45 \times 6}{ 2 \sqrt{ 6}}$

$x =\dfrac{45 \sqrt{6}}{ 2}$

8 0

3 years ago

Removing which point from the coordinate plane would make the graph a function of x? mc006-1.jpg

Marianna [84]

B. (-2,1)

By checking the x coordinates, I saw there was two -2, but the output was different, so one of them had to be taken out to make it a function.

Function: Every input must have one out must.

5 0

3 years ago