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Airida [17]
3 years ago
10

Blue light from a tunable laser is shined on a pair of closely space slits. If the laser light is changed to red light on the sa

me two slits, how will the spacing between the fringes on the distant diffraction screen change
Physics
1 answer:
Svetllana [295]3 years ago
5 0

Answer:

<em>The fringe spacing on a distant diffraction screen will increase.</em>

Explanation:

Blue light has a shorter wavelength than red light, so, changing from blue to red light is basically increasing the wavelength of the light involved in the experiment.

In the double slit experiment, the fringe spacing on a diffraction screen is calculated from the equation below

ω = zλ/d

where ω is the fringe spacing

z is the distance of the slit to the screen

λ is the wavelength of the light used

d is separation or distance between the slits

From the equation, one can see that if other parameters are held constant, <em>increasing the wavelength will lead to an increase in the spacing between the fringes, and hence, changing the light from blue to red light will increase the fringe spacing.</em>

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3 years ago
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.<br> Why are objects that fall near Earth's surface rarely in free fall?
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Explanation:

8 0
3 years ago
Read 2 more answers
A person holds a rifle horizontally and fires at a target. The bullet leaves the muzzle of the rifle with a velocity of 460 m/s.
Trava [24]

Answer:

the distance travelled from the bullet to the target  is 391m

Explanation:

Hello! To solve this exercise we must follow the following steps.

1. the bullet travels with constant speed which means that the distance traveled to the target is given by the following equation

X=(V1)(T1)

T1=\frac{X}{V1} =\frac{x}{460}

where

X=target distance

V1=bullet speed=460m/s

T1=

time it takes for the bullet to reach the target

2. The distance the sound travels is given by the following equation (it is the same as the distance from the person to the target)

X=(V2)(T2)

T2=\frac{X}{V2} =\frac{x}{340}

X=

target distance

V2= speed of sound=340m/s

T2=   time it takes the sound of the Bullet to return.

3. The total time it takes for the person to hear the bullet(T=2s) is the sum of the time it takes for the bullet to reach the target, plus the time it takes for the sound to reach the person, with the above we infer the following equation

T=T1+T2

2=T1+T2

4. Finally we use the equations found in step 1 and 2 to find the distance traveled using algebra.

2=\frac{x}{340}+\frac{x}{460} \\x(\frac{1}{340} +\frac{1}{460} )=2\\\ X= \frac{2}{(\frac{1}{340} +\frac{1}{460} )} \\\\x=391m

the distance travelled from the bullet to the target  is 391m

3 0
2 years ago
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