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MrRissso [65]
3 years ago
15

HELP PLS

Physics
2 answers:
melomori [17]3 years ago
4 0

If the field is in a vacuum, the magnetic field is the dominant factor determining the motion. Since the magnetic force is perpendicular to the direction of travel, a charged particle follows a curved path in a magnetic field. The particle continues to follow this curved path until it forms a complete circle. Another way to look at this is that the magnetic force is always perpendicular to velocity, so that it does no work on the charged particle. The particle’s kinetic energy and speed thus remain constant. The direction of motion is affected but not the speed.

A negatively charged particle moves in the plane of the paper in a region where the magnetic field is perpendicular to the paper (represented by the small × ’s—like the tails of arrows). The magnetic force is perpendicular to the velocity, so velocity changes in direction but not magnitude. The result is uniform circular motion.

Free_Kalibri [48]3 years ago
4 0
I think it would be a electron
I’m not sure if my explanation is correct but I’m gonna say it’s bc they attract ik it had to be right it’s just my explanation that’s wrong
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When the Sun is directly overhead, the intensity of sunlight reaching the ground is about 1000 W/m^{2} 2 . The Earth has a radiu
Hunter-Best [27]

Answer:

The total power associated with sunlight shining on the Earth is 8.04 × 10^10W

Explanation: Please see the attachment below

6 0
3 years ago
A 0.9 kg ball attached to a cord is whirled in a vertical circle of radius 2.5 m. Find the minimum speed needed at the top of th
lapo4ka [179]

Answer:

The minimum speed needed at the top of the circle so that the cord remains tensioned and the ball's path remains circular is approximately is 9.903 meters per second.

Explanation:

By the Principle of Energy Conservation we understand that the minimum speed needed by the ball is that speed such that maximum height reached is equal to the diameter of the vertical circle, that is:

K =U_{g} (1)

Where:

K - Translational kinetic energy, measured in joules.

U_{g} - Gravitational potential energy, measured in joules.

By definitions of translational kinetic and gravitational potential energies, we expand the equation above and clear the initial speed of the ball:

\frac{1}{2}\cdot m \cdot v^{2} = m\cdot g\cdot h

v = \sqrt{2\cdot g\cdot h} (2)

Where:

m - Mass, measured in kilograms.

v - Initial speed, measured in meters per second.

g - Gravitational acceleration, measured in meters per square second.

h - Maximum height of the ball, measured in meters.

If we know that g = 9.807\,\frac{m}{s^{2}} and h = 5\,m, then the initial speed of the ball is:

v = \sqrt{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (5\,m)}

v\approx 9.903\,\frac{m}{s}

The minimum speed needed at the top of the circle so that the cord remains tensioned and the ball's path remains circular is approximately is 9.903 meters per second.

3 0
3 years ago
The energy stored by any pair of positive charges is inversely proportional to the distance between them, and directly proportio
denpristay [2]

Answer:

 U = 25 J

Explanation:

The energy in a set of charges is given by

          U = k \sum \frac{q_i}{r_i}

in this case we have three charges of equal magnitude

          q = q₁ = q₂ = q₃

with the configuration of an equilateral triangle all distances are worth

          d = a

          U = k ( \frac{q_1q_2}{ r_1_2 } + \frac{q_1q_3}{r_1_3} + \frac{q_2q_3}{r_2_3} )

we substitute

           15 = k q² (3 / a)

            k q² /a = 5

For the second configuration a load is moved to the measured point of the other two

          d₁₃ = a

The distance to charge 2 that is at the midpoint of the other two is

          d₁₂ = d₂₃ = a / 2

           U = k (\frac{q_1q_2}{ r_1_2 } + \frac{q_1q_3}{r_1_3} + \frac{q_2q_3}{r_2_3})

            U = k q² (  \frac{2}{a} + \frac{1}{a} + \frac{2}{a} )

            U = (kq² /a) 5

substituting

            U = 5 5

            U = 25 J

5 0
3 years ago
In which orbitals would the valence electrons for selenium (Se) be placed?
LUCKY_DIMON [66]

s orbital and p orbital

hope this helps :)

8 0
4 years ago
Can you get very smart?
Mamont248 [21]

Actually according to physics there should be needed a force to move things but our mind does not produce a force ...Apart from myths ...is seems quite impossible to move a object with ur mind

-Thanks for reading

6 0
3 years ago
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