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3 years ago

HELP PLS

2 answers:

4 0

If the field is in a vacuum, the magnetic field is the dominant factor determining the motion. Since the magnetic force is perpendicular to the direction of travel, a charged particle follows a curved path in a magnetic field. The particle continues to follow this curved path until it forms a complete circle. Another way to look at this is that the magnetic force is always perpendicular to velocity, so that it does no work on the charged particle. The particle’s kinetic energy and speed thus remain constant. The direction of motion is affected but not the speed.

A negatively charged particle moves in the plane of the paper in a region where the magnetic field is perpendicular to the paper (represented by the small × ’s—like the tails of arrows). The magnetic force is perpendicular to the velocity, so velocity changes in direction but not magnitude. The result is uniform circular motion.

Free_Kalibri [48]3 years ago

4 0

I think it would be a electron
I’m not sure if my explanation is correct but I’m gonna say it’s bc they attract ik it had to be right it’s just my explanation that’s wrong

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4 years ago

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3 years ago

Important things about emotional health

atroni [7]

Answer:

The important thing about emotional health is being in control of their thoughts, feelings, and also behaviors.

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3 years ago

Read 2 more answers

The open-circuit voltage of a car battery is measured to be 12 V. During engine startup, the battery delivers 10 A to the starte

dmitriy555 [2]

Answer:

- the Thevenin equivalent circuit for the battery is uploaded below

- the battery delivered 117 watts of power to the starter motor

Explanation:

Given the data in the equation

diagram of the Thevenin equivalent circuit for the battery is uploaded below.

Current I = 10 A

Voltage 1 = 12 V

voltage 2 = 11.7 v

R = (V1 - V2) / I

R = (12-11.7)/10

R = 0.3 / 10

R = 0.03Ω

Thevenin equivalent circuit

$R_{L}$ = V2 / I = 11.7 / 10

$R_{L}$ = 1.17Ω

so, power delivered to the starter motor will be;

p = (V2)² / $R_{L}$

P = ( 11.7 V )² / 1.17Ω

p = 136.89 / 1.17

p = 117 watts

Therefore, the battery delivered 117 watts of power to the starter motor

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3 years ago

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Answer:

c. emission of electromagnetic radiation.

Explanation:

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3 years ago