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Karolina [17]
2 years ago
8

Blocks of mass 10, 30, and 90 kg are lined up from left to right in that order on a frictionless surface so each block is touchi

ng the next one. A rightward-pointing force of magnitude 32 N is applied to the left-most block. 1) What is the magnitude of the force that the left block exerts on the middle one
Physics
1 answer:
kramer2 years ago
7 0

Answer:

32N

Explanation:

The Left force exerts an opposite horizontal force of 32N on the middle object

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As an object moves, the distance it travels increases with time. Agree Disagree
egoroff_w [7]

Answer:

Agree

Explanation:

Distance is described as "how much ground an object is covered" in physics, and because the object is moving, no matter which direction, it is constantly gaining more distance. You can think of the object as a car, and as the car is moving down a highway it is gaining more and more distance as the seconds go by.

You might be confused with the term displacement, "how far out of place an object is" which in this case would be false.

Does that make sense?

3 0
2 years ago
a 4.0 kilogram ball moving at 8.0 m/s to the right collides with a 1.0 kilogram ball at rest. after the collision the 4.0 kilogr
Inga [223]
Step by step equation
7 0
3 years ago
The concept of critical density is just like the idea of escape velocity for a projectile launched from the earth. An object lau
ikadub [295]

Answer:

v = √ 2 G M/ R_{e}

Explanation:

To find the escape velocity we can use the concept of mechanical energy, where the initial point is the surface of the earth and the end point is at the maximum distance from the projectile to the Earth.

Initial

        Em₀ = K + U₀

Final

        Em_{f} =  U_{f}

The kinetic energy is k = ½ m v²

The gravitational potential energy is U = - G m M / r

r is the distance measured from the center of the Earth

How energy is conserved

       Em₀ =  Em_{f}

       ½ mv² - GmM / R_{e} = -GmM / r

       v² = 2 G M (1 /  R_{e} – 1 / r)

       v = √ 2GM (1 / R_{e} – 1 / r)

The escape velocity is that necessary to take the rocket to an infinite distance (r = ∞), whereby 1 /∞ = 0

        v = √ 2GM /  R_{e}

5 0
3 years ago
An ideal monatomic gas initially has a temperature of 300 K and a pressure of 5.79 atm. It is to expand from volume 420 cm3 to v
maxonik [38]

Answer:

a) The final pressure is 1.68 atm.

b) The work done by the gas is 305.3 J.

Explanation:

a) The final pressure of an isothermal expansion is given by:

T = \frac{PV}{nR}

T_{i} = T_{f}

\frac{P_{i}V_{i}}{nR} = \frac{P_{f}V_{f}}{nR}

Where:

P_{i}: is the initial pressure = 5.79 atm

P_{f}: is the final pressure =?

V_{i}: is the initial volume = 420 cm³

V_{f}: is the final volume = 1450 cm³

n: is the number of moles of the gas

R: is the gas constant

P_{f} = \frac{P_{i}V_{i}}{V_{f}} = \frac{5.79 atm*420 cm^{3}}{1450 cm^{3}} = 1.68 atm

Hence, the final pressure is 1.68 atm.

b) The work done by the isothermal expansion is:

W = P_{i}V_{i}ln(\frac{V_{f}}{V_{i}}) = 5.79 atm*\frac{101325 Pa}{1 atm}*420 cm^{3}*\frac{1 m^{3}}{(100 cm)^{3}}ln(\frac{1450 cm^{3}}{420 cm^{3}}) = 305.3 J

Therefore, the work done by the gas is 305.3 J.

I hope it helps you!        

3 0
3 years ago
Cooling causes a material to
e-lub [12.9K]

Answer:

whats the question?

Explanation:

4 0
3 years ago
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