All categories

3 years ago

How do you test oxygen

Chemistry

2 answers:

AleksandrR [38]3 years ago

4 0

Answer:

The glowing splint test is a test for an oxidizing gas, such as oxygen. In this test, a splint is lit, allowed to burn for a few seconds, then blown out by mouth or by shaking. Whilst the ember at the tip is still glowing hot, the splint is introduced to the gas sample that has been trapped in a vessel. Oxygen supports combustion so a good method of testing for oxygen is to take a glowing splint and place it in a sample of gas, if it re-ignites the gas is oxygen. This is a simple but effective test for oxygen.

Sedbober [7]3 years ago

3 0

Answer:

✧ $\underline{ \underline{ \large{ \tt{Test \: Of \: Oxygen \: Gas}}} }:$

To test whether the produced gas is oxygen or not , introduce a glowing matchstick in the jar containing gas. This burns with bright light. It proves that the gas in the gas jar is oxygen.

When a burning magnesium ribbon is introduced inside the gas jar , it burns with dazzling light and produces white ash of magnesium oxide. This proves that the gas jar contains oxygen.

ツ Hope I helped! ☃

☂ Have a wonderful day / night !♡

✎ $\underbrace{ \overbrace{ \mathfrak{Carry \: On \: Learning}}}$

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

You might be interested in

Please help me with dis

topjm [15]

Answer:

Explanation:

4 0

3 years ago

Triacylglycerols (triglycerides) are the form of lipids that are efficient reserves for storage of energy, and are found in adip

liraira [26]

Answer:

True

Explanation:

When we consume food, our body converts the excess amount of food in our body into triglycerides and stores it. These triacylglycerols or triglycerides, commonly known as fats, come under the category of lipids.

Triglycerides are the stored form of energy, that our body uses at the time of need.

Adipose tissues are known as fat tissues, as their main function is the storage of triglycerides in our body.

6 0

3 years ago

Citric acid (H3 C6 H5 O7) is a product of the fermentation of sucrose (C12 H22 O11) in air.

stiks02 [169]

Answer:

960.6175

Explanation:

The balanced equation shows that for every mole of sucrose used, 2 moles of citric acid are produced.

So 2.5 moles of C12H22O11 will produce 2*2.5 moles of Citric acid.

So 2.5 moles of C23H22O11 will produce 5 moles of Citric Acid.

The next step is to figure out the molar mass of Citric Acid.

There are

Hydrogen: H3 + H5 moles of hydrogen in 1 mole of Citric Acid = 8 mol H

Carbon: 1 mol of Citric Acid has 6 moles of Carbon in it = 6 mol C

Oxygen: 1 mol of Citric Acid has 7 moles of Oxygen it it =7 mol O

Hydrogen has a mass of 1 so Citric Acid has 1 * 8 grams H 8

Carbon has a mass of 12 so Citric Acid has 12 * 6 grams C 72

Oxygen has a mass of 16 so Citric Acid has 16 * 7 grams O 112

Total grams for 1 mol Citric Acid 192

The official published mass of Citric Acid is 192.1235 so because I used rounded numbers I'm a little off. It is important for any chemistry student student to know where the 192.1235 came from rather than exactly why I'm a little out. Every periodic table lists different masses for each element. If you want a better number, you will have to consult your own periodic table.

1 mol of Citric Acid = 192 grams

5 mols of Citric Acid = x

Cross multiply

1 * x = 5 * 192

x = 960 grams.

If you want to use the published amount then the answer will be 5 * 192.1235 = 960.6175

8 0

3 years ago

HURRY FOR A TEST! The ionization energies for removing successive electrons from sodium are 496 kJ/mol, 4562 kJ/mol,

prohojiy [21]

Answer:

D. The noble gas configuration has been reached.

Explanation:

8 0

3 years ago

The concentration of oxalate ion (C2O42-) in a sample can be determined by titration with a solution of permanganate ion (MnO4-)

zmey [24]

Answer:

0.3152 M

Explanation:

The reaction that takes place is:

2MnO₄⁻ + 5C₂O₄⁻² + 16H⁺ → 2Mn⁺² + 8H₂O + 10CO₂

First we calculate the MnO₄⁻ moles used up in the titration, by multiplying the volume times the concentration:

21.93 mL * 0.1725 M = 3.783 mmol MnO₄⁻

Then we convert MnO₄⁻ moles to C₂O₄⁻² moles:

3.783 mmoles MnO₄⁻ * $\frac{5mmolC_2O_4}{2mmolMnO_4}$ = 9.457 mmol C₂O₄⁻²

Finally we calculate the oxalate ion concentration, by dividing the moles by the volume:

9.457 mmol C₂O₄⁻² / 30.00 mL = 0.3152 M

6 0

3 years ago

How do you test oxygen​

How do you test oxygen