Translation
A tractor pulling a cart loaded with sugar cane travels down the straight path of a farm at a speed of 20 km / h. If at 3:00 p.m.you pass the Finca Las Margaritas, what time will you arrive at the Las Ilusiones farm, located on the same road, if the distance between the two farms is 60 km
Answer:
6.00 pm
Explanation:
Speed is given by dividing distance by time and expressed as s=d/t. Making time the subject of the formula then t=d/s where s is the speed, d is distance covered and t is the time taken. Substituting 20 km/h for s and 60 km for d then t=60/20=3 hours
Adding 3 hours to 3 pm we get 6pm
Therefore, the time to reach the destination if the speed is constantly maintained is 6.00 pm
Answer:
8954000 J
Explanation:
The formula to find kinetic energy is:
<em>Kinetic energy = </em>
<em> × mass × (velocity)²</em>
So, Kinetic energy =
× 370 × (220)²
Kinetic energy = 8954000 J
Work = Force x displacement
Force= 20N
Displacement= 0.75m
W= 20(0.75)
W= 15 Nm
Answer:
from hot toward cold. Heat moves naturally by any of three means. The processes are known as conduction, convection, and radiation. Sometimes more than one may occur at the same time.
Explanation:
The kinetic energy of this block-spring when the block has a speed (v) is given by K.E = 1/2 × (M + m/3)v².
<h3>What is kinetic energy?</h3>
Kinetic energy can be defined as a form of energy that is possessed by a person due to its motion or change in speed (acceleration).
<h3>How to calculate kinetic energy?</h3>
Mathematically, kinetic energy can be calculated by using this formula:
K.E = 1/2 × mv²
Where:
- K.E represents the kinetic energy.
- v represents the speed or velocity.
Since the mass of a segment of this spring is dm = (m/l) dx, the kinetic energy for each of its segment would be given by:
dK = 1/2 × (dm)Vx²
This ultimately implies that, the kinetic energy of this block-spring when the block has a speed (v) is given by:
K.E = 1/2 × Mv² + 1/2 × ¹∫₀((x²v²/l²)m/ldx
K.E = 1/2 × (M + m/3)v².
Read more on kinetic energy here: brainly.com/question/15848455
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