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ratelena [41]
3 years ago
6

A defibrillator is used during a heart attack to restore the heart to its normal beating pattern. A defibrillator passes 18 A of

current: through the torso of person in 2.0 ms- (a) How much charge moves during this time
Physics
1 answer:
miskamm [114]3 years ago
8 0

Answer:

q = 0.036 C

Explanation:

Given that,

Current passes through a defibrillator, I = 18 A

Time, t = 2 ms

We need to find the charge moved during this time. We know that,

Electric current = charge/time

q=It

Put all the values,

q=18\times 0.002\\\\q=0.036\ C

So, 0.036 C of charge moves during this time.

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Please tell me if this is Newton's first law, second, or third law of motion. There can be more than one of the same answer very
AfilCa [17]

Answer: Hope This Helps!

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3: Newtons third law can explain, as the cannonball is pushed forwards by the expanding high-pressure gases created by the exploding gunpowder, it pushes back on these gases. The gases push back on the cannon itself, causing it to roll backwards. Alternative answer: the cannon pushes forward on the cannonball. the reaction force is the cannonball pushing backwards on the cannon.

5 0
4 years ago
An electron is accelerated from rest by a potential difference of 412 V. It then enters a uniform magnetic field of magnitude 18
Salsk061 [2.6K]

Explanation:

Given that,

Potential difference, V = 412 V

Magnitude of magnetic field, B = 188 mT

(a) The potential energy of electron is balanced by its kinetic energy as :

eV=\dfrac{1}{2}mv^2

v is speed of the electron

v=\sqrt{\dfrac{2eV}{m}} \\\\v=\sqrt{\dfrac{2\times 1.6\times 10^{-19}\times 412}{9.1\times 10^{-31}}} \\\\v=1.2\times 10^7\ m/s

(b) When the charged particle moves in magnetic field, it will move in circular path. The radius of the circular path is given by :

r=\dfrac{mv}{eB}\\\\r=\dfrac{9.1\times 10^{-31}\times 1.2\times 10^7}{1.6\times 10^{-19}\times 188\times 10^{-3}}\\\\r=3.63\times 10^{-4}\ m

Hence, this is the required solution.                                

7 0
3 years ago
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