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serg [7]
3 years ago
15

If you are seeing a solar eclipse but you are not located in the umbra of the moon, what might you see in the sky?

Physics
1 answer:
damaskus [11]3 years ago
3 0
That is pretty tricky, I'd say you would see the moon over the sun, but not all the way.



I Hope this helps
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When two bodies at different temperatures are placed in thermal contact with each other, heat flows from the body at higher temp
Ratling [72]

Answer:

Part <em>d</em> is correct.

5 0
2 years ago
A physics student standing on the edge of a cliff throws a stone vertically downward with an initial speed of 10 m/s. The instan
gizmo_the_mogwai [7]

Answer:

The velocity just before hitting the ground is v_f = 30 m/s

Explanation:

From the question we are told that

    The initial speed is  u = 10 m/s

    The final speed is  v = 30 \ m/s

From the equations of motion we have that

      v^2 =u^2 + 2as

Where s is the distance travelled which is the height of the cliff

  So making it the subject of the the formula  we have that

        s = \frac{v^2 - u^2 }{2a}

Where a is the acceleration due to gravity with a value  a = 9.8m/s^2

       So

                  s = \frac{30^2 - 10^2 }{2 * 9.8 }

                  s = 40.8 \ m

Now we are told that was through horizontally with a speed of

      v_x =10 m/s

Which implies that this would be its velocity horizontally through out the motion

    Now it final  velocity vertically can be mathematically evaluated as

            v_y = \sqrt{2as}

Substituting values

             v_y = \sqrt{(2 * 9.8 * 40.8)}

             v_y =  28.3 \ m/s

The resultant final velocity is mathematically evaluated as

       v_f = \sqrt{v_x^2 + v_y^2}

Substituting values

       v_f = \sqrt{10^2 + 28.3^2}

       v_f = 30 m/s

   

5 0
3 years ago
what is the force between a 3 Coulomb charge and a 2 Coulomb charge separated by a distance of 5 meters?
Svetllana [295]
5,625 x 10 ⁻¹⁰ is <span>the force between a 3 Coulomb charge and a 2 Coulomb charge separated by a distance of 5 meters.</span>
5 0
3 years ago
How can people who live near rivers control flodding
dimaraw [331]
By building dams and levees . Hope this helps
8 0
3 years ago
Read 2 more answers
The effective nuclear charge experienced by the outermost electron of Na is different than the effective nuclear charge experien
Nesterboy [21]

Answer:

B) Na has a lower first ionization energy than Ne.  

Explanation:

The atomic number¹ for Na has a value of 11 while in the case of Ne this value is 10. That means that Sodium (Na) has a total number of 11 protons, 11 neutrons and 11 electrons (since it is electrically neutral²). For the case of Neon (Ne) it has 10 protons, 10 neutrons and 10 electrons.

As the atomic number increases, the atomic radius³ shrinks (the orbitals are closer to the nucleus) as a consequence of the electric force. For the case of sodium (Na) the electron in the outermost orbital will experience a lower electric force than the electron placed in the outermost orbital in the atom of Neon (Ne).

Although, the sodium’s atom has more protons and therefore electrons, these eleven electrons will be organized according with the electronic configuration⁴ in the different shells (orbitals) of probabilities of their positions around the atom.

The electronic configuration for Na is:

1s²2s²2p⁶3s¹

The electronic configuration for Ne is:

1s²2s²2p⁶

Since Na needs another orbital to placed its outermost electron, the atomic radius will have a greater value than Ne. The electric force is inversely proportional to the square of the distance between two charged particles, as is established in Coulomb’s law:

F = \kappa_{0} \frac{q1q2}{r^{2}}    (1)

Where q1 and q2 are the charges, \kappa_{0} is the proportionality constant and r is the distance between the two charges.

Hence, the electron in the outermost orbital of Ne is submitted to a greater electric force according with equation 1, the required energy to remove it (ionization energy⁵) will be greater than in the case of Na (<u>for that case will be the first ionization energy</u>).

¹Atomic number: The number of protons or electrons in an atom.

²Electricaly neutral: All the charges are balanced (same number of positive charges and negative charges).

³Atomic radius: Distance between the center of the nucleus and an electron placed in the outermost orbital for a specific atom.

⁴Electronic configuration: Show how the electrons of an atom will be arranged in different orbitals according with the fact that each orbital has a specific number of electrons that can be held.

⁵Ionization energy: Energy required to remove an electron from an atom.

Key values:

First ionization energy of Na: 495 kJ/mol

First ionization energy of Ne: 2080 kJ/mol

Atomic radius of Na: 2.27 Å

Atomic radius of Ne: 1.54 Å

Atomic number of Na: 11

Atomic number of Ne: 10

3 0
3 years ago
Read 2 more answers
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