Answer:
a.
Period = π
Amplitude = 4
b.
Maximum at: x = 0, π and 2π
Minimum at: x = π/2 and 3π/2
Zeros at: x = π/4, 3π/4, 5π/4 and 7π/4
Step-by-step explanation:
Part a:
Amplitude represents the half of the distance between the maximum point and the minimum point of the function. So the easy way to find the amplitude is: Find the difference between maximum and minimum value of the function and divide the difference by 2.
So, amplitude will be: ![\frac{Maximum-Minimum}{2}=\frac{4-(-4)}{2}=\frac{8}{2}=4](https://tex.z-dn.net/?f=%5Cfrac%7BMaximum-Minimum%7D%7B2%7D%3D%5Cfrac%7B4-%28-4%29%7D%7B2%7D%3D%5Cfrac%7B8%7D%7B2%7D%3D4)
Therefore, the amplitude of the function is 4.
Period is the time in which the function completes its one cycle. From the graph we can see that cosine started at 0 and completed its cycle at π. After π the same value starts to repeat. So the period of the given cosine function is π.
Part b:
From the graph we can see that the maximum values occur at the following points: x = 0, π and 2π
The scale on x-axis between 0 and π is divided into 4 squares, so each square represents π/4
Therefore, the minimum value occurs at x = π/2 and 3π/2
Zeros occur where the graph crosses the x-axis. So the zeros occur at the following points: π/4, 3π/4, 5π/4 and 7π/4
Answer:
6.92 x 1,000= 6,920
Step-by-step explanation: Hope this helps
<u><em>A</em></u> would be correct hope I helped.
12 lawns/9 hours = 1.33 lawns per hour
Answer:
Step-by-step explanation:
x can be anything so let’s use 0, 1, 2, and 3 for x values
to find the y values, we just plug in the x values into the equation
when x = 0
y = 5/4(0) -2
y = 0 -2
y = -2
(0, -2) (x = 0, y = -2)
when x = 1
y = 5/4(1) -2
y = 5/4 -2
y = 5/4 -8/4
y = -3/4
(1, -3/4) (x = 1, y = -3/4)
when x = 2
y = 5/4(2) -2
y = 10/4 -2
y = 5/2 -4/2
y = 1/2
(2, 1/2) (x = 2, y = 1/2)
when x = 3
y = 5/4(3) -2
y = 15/4 -2
y = 15/4 -8/4
y = 7/4
(3, 7/4) (x = 3, y = 7/4)