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3 years ago

Please do it to me thank alot

Physics

1 answer:

faltersainse [42]3 years ago

8 0

Answer:

See explanations below

Explanation:

For resistors in series, the will be added for those in parallel, we will take the sum of their reciprocal

A) 3 2ohms resistors in series

Equivalent resistance = 2 + 2 + 2

Equivalent resistance = 6ohms

B) 2 4 ohms resisstors in parallal

1/R = 1/4 + 1/4

1/R = 2/4

R = 4/2

R = 4ohms

Equivalent resistance is 2ohms

C) 4 ohms with in series with 8ohms = 4 + 8

Equivalent resistance = 4 + 8

Equivalent resistance = 12ohms

D) 4 ohms and 2 ohms in parallel is expressed as;

1/R = 1/4 + 1/2

1/R = 1+2/4

1/R = 3/4

R = 4/3

4/3 ohms in series with 6ohms

Equivalent resistance = 4/3 + 6

Equivalent resistance =4+18/3

Equivalent resistance = 22/3 ohms

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Answer:

A) The possible algebraic signs will either be both positive (+) or both negative (-) charged since the 2 objects are repelling each other to stretch the string.

B) Magnitude of charges = 1.206 × 10^(-6) C

Explanation:

We are given;

Spring constant;k = 350 N/m

Spring length;L = 0.39 m

Stretched length of spring;x = 0.022 m

A) The spring stretches by 0.022m. Therefore, the total force is (350 × 0.022) N = 7.7N. The charged objects will either be both positive (+) or both negative (-) charged since they are repelling each other to stretch the string.

B) Force (F) required to stretch spring is given by the formula;

F = kx

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F = (350 × 0.022)

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Now, if we assume point charges, then the distance (r) between them will be given as:

r = (0.39 + 0.022) = 0.412 m

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F = k(q1×q2)/r²

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Making q1 × q2 the subject, we have;

(q1 × q2) = Fr²/k = 7.7 × 0.412²/(8.99 × 10^(9))

(q1 × q2) = 14.54 × 10^(-11) C

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q = √(14.54 × 10^(-11)) = 1.206 × 10^(-6) C

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4 years ago

A batter hits a foul ball. The 0.140-kg baseball that was approaching him at 40.0 m/s leaves the bat at 30.0 m/s in a direction

lara31 [8.8K]

<h3>Answer</h3><h3>7 Ns</h3><h3>Explanation</h3>

Given in the question,

mass of foul ball = 0.140 kg

initial speed with which ball was hit with the bat = 30 m/s

final speed = 40 m/s

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So, to the solve the question we will use pythagorus theorem

<h3>Hypotenuse² = base² + height²</h3>

Here,

Hypotenuse= Magnitude of impulse

Base = 1st change of momentum

height = 2nd change of momentum

1st impulse (1st change of momentum)

p = m(1)v(1) = (0.14 kg)(40.0 m/s) = 5.6 kg m / s = 5.6 N s

2nd impulse (2nd change of momentum)

p = m(2)v(2) = (0.14 kg)(30.0 m/s) = 4.2 kg m / s = 4.2 N s

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We have two solenoids: solenoid 2 has twice the diameter, half the length, and twice as many turns as solenoid 1. The current in

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Answer:

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Now, if we write a similar formula for solenoid 2, given that it has :

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2) twice as many turns as solenoid 1. Then $N_2=2\,N_1$

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