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4 years ago

Equal and opposite forces that act on the same object are called

Physics

1 answer:

inessss [21]4 years ago

4 0

Answer:Balance Forces

Explanation:

Balanced Forces are equal in magnitude and opposite in direction that acts on the same body. Whenever balanced forces act on an object the object is either still or moving in the same direction with constant velocity.

example of Balanced Forces are

Consider a block lying on the ground and is being pulled by two forces of equal magnitude but in acting in the opposite direction. As a result, the block is at rest.

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An engine is designed to obtain energy from the temperature gradient of the ocean. What is the thermodynamic efficiency of such

rewona [7]

Answer:

0.035 (3.5 %)

Explanation:

The thermodynamic efficiency is given by:

$\eta = 1 - \frac{T_C}{T_H}$

where

$T_C$ is the cold temperature

$T_H$ is the hot temperature

In this problem we have

$T_C = 5 ^{\circ}C+ 273 = 278 KT_H = 15^{\circ}C+273 = 288 K$

So the efficiency is

$\eta = 1 - \frac{278 K}{288 K}=0.035$

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3 years ago

A student pushes a chair into a desk. If the student's push is the action force, then what is the reaction force in this example

Brrunno [24]

Answer: C

Explanation:

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3 years ago

Read 2 more answers

A rocket blasts off vertically from rest on the launch pad with an upward acceleration of 2.90 m/s2 . At 20.0s after blastoff, t

Brilliant_brown [7]

Answer:

A) 580m

B) 0 m/s

C) 9.8m/s^2

D) downward

E) 10.87s

F) 106.62 m/s

Explanation:

A) The distance traveled by the rocket is calculated by using the following expression:

$y=\frac{1}{2}at^2$

a: acceleration of the rocket = 2.90 m/s^2

t: time of the flight = 20.0 s

$y=\frac{1}{2}(2.90\frac{m}{s^2})(20.0s)^2=580m$

B) In the highest point the rocket has a velocity with magnitude zero v = 0m/s because there the rocket stops.

C) The engines of the rocket suddenly fails in the highest point. There, the acceleration of the rocket is due to the gravitational force, that is 9.8 m/s^2

D) The acceleration points downward

E) The time the rocket takes to return to the ground is given by:

$t=\sqrt{\frac{2y}{g}}=\sqrt{\frac{2(580m)}{9.8m/s^2}}=10.87s$