A the entropy of the reaction I think ion know if that’s correct
Answer:
A
Explanation:
i feel it is correct
in the sense that it dwpends on the presence of 4different antigens
Consider the motion of the car before brakes are applied:
v₀ = maximum initial velocity of the car before the brakes are applied
t = reaction time = 0.50 s
x₀ = distance traveled by the car before brakes are applied
since car moves at constant speed before brakes are applied
Using the equation
x₀ = v₀ t
x₀ = v₀ (0.50)
Consider the motion after brakes are applied :
v₀ = initial velocity of the car before the brakes are applied
a = acceleration = - 10 m/s²
v = final velocity of the car after it comes to stop = 0 m/s
x = stopping distance = initial distance - distance traveled before applying the brakes = 38 - x₀ = 38 - v₀ (0.50)
Using the equation
v² = v²₀ + 2 a x
inserting the values
0² = v²₀ + 2 (- 10) (38 - v₀ (0.50))
v²₀ = 20 (38 - v₀ (0.50))
v₀ = 23 m/s
Answer:
The correct option is;
Sphere I is positively charged and sphere II is negatively charged
Explanation:
The charging of the spheres by induction is achieved by introducing a charge to the metal spheres that are insulated from the ground to prevent loss of charge by placing them on insulating stand
The two spheres are brought into contact by the connection of a conducting wire between the spheres I and II
The presence of the positively charged sphere III draws attracts electrons towards sphere II while the net positive charge moves towards sphere I
While the spheres I and II are still polarized, the conducting wire is removed while the presence of sphere III continues to keep sphere II negative compared to sphere I
After removing the connecting wire, sphere III is removed leaving the excess negative charge on sphere II and the excess positive charge on sphere I
The net charges then evenly redistribute themselves on each sphere creating two oppositely charged spheres.
Answer:
See bolded below.
Explanation:
Consider the " Before " and " After. " " Before, " this particle 1 was trying to catch up with this particle 2, and " after " particle one had collided with particle two. Take a look at the attachment below for a more detailed examination.
Here is how this will play out. Particle 1, with great velocity, will hit particle 2, which would mean that Particle 2 has less velocity than Particle 1. Now after the collision, energy is transferred to Particle 2, and while Particle 1 has now stopped in it's tracks, Particle 2 - with more energy than before - will continue as long as it has to before friction eventually brings it to a stop.
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From this we can conclude that Vf, from the picture below, must have less energy than V1, but more energy than V2 - and vice versa.
