Which of the following is NOT an early sign of heat illness?

How much charge must pass by a point in a wire in 1.5 s for the current inb the wire to be 2.0 A?

skelet666 [1.2K]

Answer:

3 Coulombs

Explanation:

Q = Current x time

Q = 2.0 x 1.5

Q = 3 Coulombs

3 0

4 years ago

The first-order rearrangement of CH3NC is measured to have a rate constant of 3.61 × 10–15 s–1 at 298 K and a rate constant of 8

netineya [11]

Answer:

The activation energy for this reaction, Ea = 159.98 kJ/mol

Explanation:

Using the Arrhenius equation as:

$ln\frac {K_2}{K_1}=-\frac {E_a}{R}\times (\frac {1}{T_2}-\frac {1}{T_1})$

Where, Ea is the activation energy.

R is the gas constant having value 8.314 J/K.mol

K₂ and K₁ are the rate constants

T₂ and T₁ are the temperature values in kelvin.

Given:

K₂ = 8.66×10⁻⁷ s⁻¹ , T₂ = 425 K

K₁ = 3.61×10⁻¹⁵ s⁻¹ , T₁ = 298 K

Applying in the equation as:

$ln\frac {8.66\times 10^{-7}}{3.61\times 10^{-15}}=-\frac {E_a}{8.314}\times (\frac {1}{425}-\frac {1}{298})$

Solving for Ea as:

Ea = 159982.23 J /mol

1 J/mol = 10⁻³ kJ/mol

Ea = 159.98 kJ/mol

7 0

3 years ago

When a man stands on a bathroom scale here on Earth, it reads 640 N . Assume each planet to be a perfect sphere with the followi

noname [10]

Answer:

242.19702 N

578.46718 N

681.02785 N

Explanation:

M = Mass of the corresponding planet

r = Radius of the corresponding planet

g = Acceleration due to gravity = 9.81 m/s²

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

Mass of person

$m=\frac{W}{g}\\\Rightarrow m=\frac{640}{9.81}=65.23955\ kg$

Mass is the property of an object, it is constant irrespective of the forces acting on it so the mass of the person on each planet would be the same.

Gravitational force on Mars

$F=\frac{GMm}{r^2}\\\Rightarrow F=\frac{6.67\times 10^{-11}\times 6.419\times 10^{23}\times 65.23955}{(3.396\times 10^{6})^2}\\\Rightarrow F=242.19702\ N$

Magnitude of the gravitational force Mars would exert on the man if he stood on its surface is 242.19702 N

Gravitational force on Venus

$F=\frac{GMm}{r^2}\\\Rightarrow F=\frac{6.67\times 10^{-11}\times 4.869\times 10^{24}\times 65.23955}{(6.052\times 10^{6})^2}\\\Rightarrow F=578.46718\ N$

Magnitude of the gravitational force Venus would exert on the man if he stood on its surface is 578.46718 N

Gravitational force on Saturn

$F=\frac{GMm}{r^2}\\\Rightarrow F=\frac{6.67\times 10^{-11}\times 5.685\times 10^{26}\times 65.23955}{(6.027\times 10^{7})^2}\\\Rightarrow F=681.02785\ N$

Magnitude of the gravitational force Saturn would exert on the man if he stood on its surface is 681.02785 N

6 0

4 years ago

You measure an electric field of 1.36×106 N/C at a distance of 0.158 m from a point charge. There is no other source of electric

marysya [2.9K]

Answer:

The Electric flux will be $0.42\times10^6\ \rm N.m^2/C$

Explanation:

Given

Strength of the Electric Field at a distance of 0.158 m from the point charge is

$E=1.36\times10^6\ \rm N/C$

We know that the flux of the Electric Field can be calculated by using Gauss Law which is given by

$\int E.dA=\dfrac{q_{in}}{\epsilon_0}\\$

Let consider a sphere of radius 0.158 m as Gaussian Surface at a distance of 0.158 m from the point charge and Let $\phi$ be the flux of the Electric Field coming out\passing through it which is given by

$\phi=\int E.dA=1.36\times10^6 \times4\pi \times 0.158^2\\\\=0.42\times10^6\ \rm N.m^2/C$

It can be observed that same amount of flux which is passing through the Gaussian sphere of radius 0.158 is also passing through the Gaussian sphere of radius 0.142 m at a distance of 0.142 m from its centre.

Also it can be observed that the charge inside the two Gaussian Sphere mentioned have same value so the Flux of electric field through them will also be same.

So the electric flux through the surface of sphere that has given charge at its centre and that has radius 0.142 m is $0.42\times10^6\ \rm N.m^2/C$

8 0

3 years ago

Which of the following is a trend in the health sciences

forsale [732]

Answer

more patient-centered care / advancing technology / integrative medicine

5 0

3 years ago

Read 2 more answers